Answer:
The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
Explanation:
To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.
By definition it is known that the conservation of the moment is given by:

Our values are given by,

As the skater 1 run in x direction, there is not component in Y direction. Then,
Skate 1:


Skate 2:


Then, if we applying the formula in X direction:
m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}
75*5.45-75*1.41=(75+75)v_{fx}
Re-arrange and solving for v_{fx}
v_{fx}=\frac{4.04}{2}
v_{fx}=2.02m/s
Now applying the formula in Y direction:




Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
While falling, both the sheet of paper and the paper ball experience air resistance. But the surface area of the sheet is much more than that of the spherical ball. And air resistance varies directly with surface area. Hence the sheet experiences more air resistance than the ball and it falls more slowly than the paper ball.
Hope that helps!
Answer:
346.70015 m/s
Explanation:
In the x axis speed is

In the y axis

The resultant velocity is given by

The magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean is 346.70015 m/s
Explanation:
Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one meter.
Answer;
=84 kwh
Explanation;
Electrical energy = 1000 watts
1000 watt = 1 kilo watt
1 week = 7 days
Number of hours = 7 × 12× = 84 hours
Consumption
= 1 kw × 84 hours
= 84 kwh