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3 years ago

1)

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

10 people didn't have either tickets

Xelga [282]3 years ago

7 0

40+30+20=90 (number of people with tickets; out of 100)
100-90=10
10 people had neither basketball nor football season tickets

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How many 5/6s are in 3 and 1/3

Zielflug [23.3K]

There is 3.6 5/6s in 3
There is 0.4 5/6s in 1/3

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3 years ago

-3x-6=12 what does x equal

grandymaker [24]

Answer:

-6

Step-by-step explanation:

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3 years ago

What else would need to be congruent to show that ABC DEF by SAS? E AA. А B OA. BC = EF B. CF OC. ZA ZD D. AC = OF F Given: AC =

serg [7]

The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let $$&\overline{A B} \cong \overline{D E} \\$ and $$&\overline{A C} \cong \overline{D F}$

Angle between $\overline{A B}$ and $\overline{A C}$ exists $\angle A$ .

Angle between $\overline{D E}$ and $\overline{D F}$ exists $\angle D$ .

Therefore, $\triangle A B C \cong \triangle D E F$ by SAS, if $\angle A \cong \angle D$$ .

<h3>What is SAS congruence property?</h3>

Given:

$$&\overline{A B} \cong \overline{D E} \\$ and

$$&\overline{A C} \cong \overline{D F}$

According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let $$&\overline{A B} \cong \overline{D E} \\$ and $$&\overline{A C} \cong \overline{D F}$

Angle between $\overline{A B}$ and $\overline{A C}$ exists $\angle A$ .

Angle between $\overline{D E}$ and $\overline{D F}$ exists $\angle D$ .

Therefore, $\triangle A B C \cong \triangle D E F$ by SAS, if $\angle A \cong \angle D$$ .

To learn more about SAS congruence property refer to:

brainly.com/question/19807547

#SPJ9

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2 years ago

How do you write 37. 4 in scientific notation?

Natali [406]

Answer:

3.74 × 10 or 3.74 × 10^1

Step-by-step explanation:

Hope This Helps!

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3 years ago

a state issues car license plates with three letters followed by three numbers (for example, fgh831 or bbb222). how many differe

vova2212 [387]

Answer:

17576000 different License plates are possible.

Step-by-step explanation:

Here we will use repetitive permutations.

First 3 digits of the license plates have letters from a to z and next 3 digits have numbers from 0 to 9.

Now, 26 letters ( a to z ) can take 3 positions with repetition in $26^{3}$ ways.

And 10 numbers ( 0 to 9 ) can take 3 positions with repetition in $10^{3}$ ways.

So the total number of license plates that can be made = $26^{3}$ $\times$ $10^{3}$ = 17576 $\times$ 1000 = 17576000 plates.

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3 years ago