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Pie
3 years ago
7

Find two values for k such that the trinomial x2 – 7x + k can be factored over the integers. Explain your reasoning.

Mathematics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

1) For a = 1: b = 6 and k = 6, 2) For a = 3: b = 4 and k = 12

Step-by-step explanation:

The polynomial y = x^{2} - 7\cdot x + k is a second-order polynomial of the form (x-a)\cdot (x-b) = x^{2}-(a+b)\cdot x + a\cdot b. By direct comparison, we construct the following system of equations:

a + b = 7 (1)

a\cdot b = k (2)

By (1) we know that there are a family of pairs such that the system of equations is satisfied. Let suppose that both a and b are integers. We assume two arbitrary integers for a:

1) a = 1

b = 7 - a

b = 6

a\cdot b = k

k = (6)\cdot (1)

k = 6

2) a = 3

b = 7 - a

b = 4

a\cdot b = k

k = (3)\cdot (4)

k = 12

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<span>Compound  interest  formula</span>

A=P(1+ \frac{r}{n} )^{nt}

 

Where

<span>
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P = the Principal (the initial amount of money) 
r = annual interest rate</span>

t = time

<span>n= number of times compounded in one t






Remark
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r is generally a percentage like 3%, 7% etc and are applied in the formula as 0.03, 0.07..., 

the interest is compounded generally annually (n=1), quarterly (n=4), monthly (n=12), etc...

t is in years,


In our problem:

</span>

A= 30 000

P =20 000

r = 15%=0.15

time = t = ?

n= 4

applying the formula:

A=P(1+ \frac{r}{n} )^{nt}\\\\30,000=20,000(1+ \frac{0.15}{4} )^{4t}\\\\ \displaystyle{\frac{30,000}{20,000} =(1.0375)^{4t}

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3 years ago
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Step-by-step explanation:

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4 0
3 years ago
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Vadim26 [7]

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therefore,

\displaystyle 5\int  {x}^{4} \, dx

recall exponent integration rule:

\displaystyle \int {x} ^{n}  \, dx  =  \frac{ {x}^{n + 1} }{n + 1}

so let,

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Thus integrate:

\displaystyle  =  5\left( \frac{ {x}^{4+ 1} }{4 +  1}  \right)

simplify addition:

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reduce fraction:

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finally we of course have to add the constant of integration:

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QveST [7]

Answer:

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Since three times as many people voted for the zoo, we can see that 120/3=40, so 40 people chose the aquarium.

To find the total number of students, we add 120 and 40 to get <u>160</u>

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