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Nady [450]
3 years ago
5

How to end behavior​

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

stop and think to your self about what you are doing and walk away form the problem

Step-by-step explanation:

it really dose help

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Write the equation of the line in point slope form for a horizontal line that passes through (5,-6)
denis-greek [22]

Answer:

y=-6

Step-by-step explanation:

y+6=0(x-5)

Solve

y=-6

7 0
3 years ago
If 6 cups of cheese serves 30 people how cups of cheese serve 50
bezimeni [28]
6 cups of cheese servings times 5 = 30
10 cups of cheese servings time 5 = 50
So , it's 10 cups of cheese servings.
4 0
3 years ago
Read 2 more answers
Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle
Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x+3)^{2} +(y-4)^{2}=r^{2}

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

r=\sqrt{(2-4)^{2}+(-6+3)^{2}}

r=\sqrt{(-2)^{2}+(-3)^{2}}

r=\sqrt{13}\ units

The equation of the circle is equal to

(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}

(x+3)^{2} +(y-4)^{2}=13

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

(10+3)^{2} +(4-4)^{2}=13

(13)^{2} +(0)^{2}=13

169=13 -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x-1)^{2} +(y-3)^{2}=r^{2}

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

r=\sqrt{(6-3)^{2}+(2-1)^{2}}

r=\sqrt{(3)^{2}+(1)^{2}}

r=\sqrt{10}\ units

The equation of the circle is equal to

(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}

(x-1)^{2} +(y-3)^{2}=10

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

(11-1)^{2} +(5-3)^{2}=10

(10)^{2} +(2)^{2}=10

104=10 -----> is not true

therefore

The point is not on the circle

The statement is false

7 0
3 years ago
(50 points)<br><br><br><br> NEED ANSWER ASAPPPP:)
lbvjy [14]
5-10(|0.8-3/6|)

5-10(|1/5|)

5-(10)(0.2)

5-2

=3, so C would be your best answer. 
5 0
3 years ago
Read 2 more answers
Please help with the question
Artyom0805 [142]

I find it convenient to look at the differences and the rate at which those differences are made up.

8. Jim is closing the $150 gap at the rate of $7.50 per week. He will catch up in

... 150/(7.5/week) = 20 weeks

9. At noon, the price of Stock A has increased by 0.05×3 = 0.15, so is now $15.90, which is $0.63 more than Stock B at that time. The prices are closing the gap at the rate of $0.05 +0.13 = $0.18 per hour, so will be the same after

... $0.63/($0.18/hour) = 3.5 hours . . . . after noon, at 3:30 pm

_____

You can also write and solve equations for the prices of the stocks. Or you can use a graphing calculator to tell you the solution. When equations are involved, I like to solve them the simplest possible way: let technology do it.

You are given the value at a time, and the rate of change of that value, so the equations are easily written in point-slope form. You will note that the common price at 3:30 pm (15.5 hours after midnight) is one that is not a whole number of cents. (That's usually OK for when trading stocks.)

4 0
3 years ago
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