What is the equivalent rate of 9/15/18?

1 answer:

6 0

Here, the number is = 9/15/18
We can re-write it as: 9 /15*18 = 9/270 = 1/30

In short, Your Answer would be 1/30

Hope this helps!

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With a headwind, a plane traveled 390 mi in 1.5 h. Let x represent the plane’s speed (excluding wind speed) and let y represent

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Find the domain and range of the relation: {(–20, 11), (6, –8), (1, –20), (–13, 13)}

user100 [1]

Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

Domain: {-20, -13, 1, 6}

Range: {-20, -8, 11, 13}

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3 years ago

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$