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3 years ago

What is the equivalent rate of 9/15/18?

1 answer:

6 0

Here, the number is = 9/15/18
We can re-write it as: 9 /15*18 = 9/270 = 1/30

In short, Your Answer would be 1/30

Hope this helps!

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X/5+ 7 = y Solve for x pls hurry

Setler [38]

Answer:

x=5y-35

Step-by-step explanation:

3 0

2 years ago

Julia makes friendship bracelets. She was recently given nine bracelets from different people. At Christmas, she plans to give a

sergey [27]

Answer:

The number of bracelets with she start are 48.

Step-by-step explanation:

Given:

Julia was recently given 9 bracelets. She plans to give 1/3 of her bracelets. She will be left with 23.

Now, we need to find with how many did she start.

Let the bracelets with she start be $x$ .

She plans to give $\frac{1}{3}ofx$ = $\frac{x}{3}$ .

According to question:

$x-9-\frac{x}{3}=23$

On solving the equation:

$\frac{3x-27-x}{3} =23$

Multiplying both sides by 3 we get:

$3x-27-x=69$

$2x-27=69$

Adding both sides by 27 and then dividing by 2 we get:

$x=48$

Therefore, the number of bracelets with she start are 48.

6 0

2 years ago

Parallelogram ABCD is similar to the parallelogram EFGH. What is the length of GH?

laiz [17]

Answer:

2 in

Step-by-step explanation:

3 0

2 years ago

The advertised size of a computer or television screen is actually the length of the diagonal of

andreyandreev [35.5K]

Answer:

37.5 cm

Step-by-step explanation:

See attached for reference.

let the diagonal be x,

By Pythagorean formula:

x² = (22.5)² + (30)²

x = √[(22.5)² + (30)²]

x = 37.5 cm

4 0

2 years ago

Verify identity: (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

2 years ago