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2 years ago

What is a correct expansion of (3x + 2)(3x^2 + 4)

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

5 0

All we need to do is use FOIL here to multiply these.

(3x + 2)(3x^2 + 4)

9x^3 + 12x + 6x^2 + 8

Simplify.

Rearrange terms.

9x^3 + 6x^2 + 12x + 8 is the expanded form of the original binomials.

4vir4ik [10]2 years ago

5 0

The answer is: 3x·3x^2+3x·4+2·3x^2+2·4 APEX

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Which of the following us the graph of you=5

JulijaS [17]

Y = 5

i think that what you meant

so the point will be (0,5) and will be a horizontal line at y=5

hope that helps

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2 years ago

Round 713,923 to the nearest hundred.

jeyben [28]

Answer:

713,7923 to the nearest hundred is 713,900

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2 years ago

Use the following regression results to answer the remaining questions. Y measures average hourly earnings AHE in U.S. dollars f

Ulleksa [173]

Answer:

Check the explanation

Step-by-step explanation:

Y = 11.5 + 4.5*X1 -2.5*X2 +0.7*X3+1.6*X4 -2.4*X5 -2.8*X6

FOR JANE

X1 =1 , X2 =1 , X3 =5 , X4 =0 ,X5=0, X6=1

SO,

Y =11.5+(4.5*1)-(2.5*1)+(0.7*5)+0+0-(2.8*1)

= 14.2

..........................

FOR Sophie

X1 =1 , X2 =1 , X3 =10 , X4 =1 ,X5=0, X6=0

so,

Y =11.5+(4.5*1)-(2.5*1)+(0.7*10)+ (1.6*1)+0+0

= 22.1

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2 years ago

What is the value of 7x2 - 10, when x = 6?

cestrela7 [59]

Answer:

242

Step-by-step explanation:

7(6*6)-10

7(36)-10

252-10

=242

7 0

2 years ago

The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

So, According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of The inscribed circle

So, the center of The inscribed circle is the point S

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

So, According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of The circumscribed circle

So, the center of The circumscribed circle is the point P

5 0

2 years ago