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4 years ago

If the length of the ramp is 2m and the height of the ramp is 1m , what is the mechanical advantage?

Physics

1 answer:

slamgirl [31]4 years ago

5 0

Answer:

Mechanical Advantage is 2

Explanation:

M.A = length of ramp / height of ramp

= 2/1

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Two automobiles traveling at right angles to each other collide and stick together. Car A has a mass of 1200 kg and had a speed

sergij07 [2.7K]

Answer:

$v_{B0}=15.73 m/s$

Explanation:

We can use the conservation of momentum. The initial momentum is equal to the final momentum:

x-coordinate

$p_{0x}=p_{fx}$

$m_{A}v_{A0}=(m_{A}+m_{B})v_{cx}$

$m_{A}v_{A0}=(m_{A}+m_{B})v_{c}cos(40)$ (1)

y-coordinate

$p_{0y}=p_{fy}$

$m_{B}v_{B0}=(m_{A}+m_{B})v_{cy}$

$m_{B}v_{B0}=(m_{A}+m_{B})v_{c}sin(40)$ (2)

We can divide equations (2) and (1):

$\frac{m_{B}v_{B0}}{m_{A}v_{A0}}=\frac{sin(40)}{cos(40)}$

$\frac{m_{B}v_{B0}}{m_{A}v_{A0}}=tan(40)$

$v_{B0}=\frac{m_{A}v_{A0}}{m_{B}}*tan(40)$

$v_{B0}=\frac{1200*25}{1600}*tan(40)$

$v_{B0}=15.73 m/s$

I hope it helps you!

4 0

4 years ago

Read 2 more answers

A railroad freight car rolls on a track at 3.50 m/s toward two identical coupled freight cars, which are rolling in the same dir

ladessa [460]

Answer:

Explanation:

Hello! To solve this problem we must be clear about the concept of energy conservation, and kinetic energy with the following sentence

The kinetic energy of the two cars (v = 1.2m / S) plus the kinetic energy of the third car (v = 3.5m / S) must be equal to the kinetic energy of the three cars together.

The kinetic energy is calculated by the following equation.

$E=0.5mV^2$

m= mass of the cars=26500kg

V=speed

E=kinetic energy

taking into account the above, the following equation is inferred

1= the cars are separated

2= the cars are togheter

E1=E2

$E1=0.5mV1^2+0.5mV1^2+0.5m(Va)^2$

where

m= mass of each car

V1= 1.2m/s

Va=3.5,m/S

$E2=0.5(3)(m)V^2$

m= mass of each car

V=speed (in m/s) of the three coupled cars after the first couples with the other two

Solving

$0.5mV1^2+0.5mV1^2+0.5m(Va)^2=0.5(3)(m)V^2$

$V1^2+V1^2+(Va)^2=(3)V^2.\\2V1^2+(Va)^2=(3)V^2\\V^2=\frac{2V1^2+(Va)^2}{3} \\$

$V=\sqrt{\frac{2V1^2+(Va)^2}{3}} \\V=\sqrt{\frac{2(1.2)^2+(3.5)^2}{3}} \\\\V=2.245m/s$

the speed of the three coupled cars after the first couples with the other two is 2.245m/s

7 0

3 years ago

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PLEASE HELP WILL GIVE EXTRA POINTS

wolverine [178]

Sorry but you tell me not to ask for help or answers but you want them yourself

6 0

3 years ago

Hello....I need help with this question.

musickatia [10]

Answer:

3.2 m/s²

Explanation:

Acceleration can be calculated as:

v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time)

25 m/s = 9 m/s + a(5 s) (a is unknown)

16 m/s = a(5 s)

a = 3.2 m/s²

We assume that this is a uniform acceleration (meaning that the velocity increases at an equal rate for those 5 seconds).

6 0

3 years ago

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When would an atom act like a magnet?

sladkih [1.3K]

Because they have no opposing fields to cancel their effects, these electrons have an orbital magnetic. Magnetic moments<span> come from the moments of all of its </span>atoms<span>.</span>

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3 years ago