Well you have to minus the 4.5 to 5.2 and the answer to that would be -11.5 and calculated that to be 4.5
This answer is true the earth always stays at one speed
The force is 2.0 N east
Explanation:
The impulse exerted by a force is defined as the product between the force itself and the time interval during which the force is applied. Mathematically, it is equal to the change in momentum experienced by the object on which the force is acting:
Where
I is the impulse
F is the force
is the time interval during which the force is applied
is the change in momentum
In this problem,
is the time interval
(east) is the impulse
Therefore, the magnitude of the force is
And the direction is the same as the impulse (east).
Learn more about impulse and change in momentum:
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In the context of the loop and junction rules for electrical circuits, a junction is where three or more wires are joined.
Answer: Option 2
<u>Explanation:
</u>
An electrical circuits consists of many points like branch, loop, junction, series, bridge, etc. So, loops are the ones where the output of one circuit will act as feedback of the same circuit. If two or more wires passes through a single point, then that point is termed as junction.
If two or three junction connect each other they are termed as branch. Like these several other parameters are there with different rules in the circuit system. For electrical circuits, junction and loop rules state that a junction is the point where more wires joined together.
Answer:
For C1, Q = 1.6125×10⁻³ C
For C2, Q = 6.25×10⁻⁴ C
Explanation:
Note: Since the capacitors are connected in parallel, The voltage across each of them is equal.
From the question,
Q = CV........................ Equation 1
Where Q = Charge on the capacitor, V = Voltage across the capacitor, C = Capacitance of the capacitor.
For the first capacitor,
Q = C1V............. Equation 2
Where C1 = 6.45 μF= 6.45×10⁻⁶ F, V = 250 V
Substitute into equation 2
Q = (6.45×10⁻⁶ )(250)
Q = 1.6125×10⁻³ C.
For the the second capacitor,
Q = C2V............. Equation 3
Given: C2 = 2.50 μF = 2.5×10⁻⁶ F, V = 250 V
Q = (2.5×10⁻⁶ )(250)
Q = 6.25×10⁻⁴ C
