FOR THAT YOU NEED TO UNDERSTAND WHAT ACTUALLY KINETIC ENERGY IS.
It is a form of energy which is caused due to motion, when the ball is kicked, it is send into motion thus it gains kinetic energy, how come energy came from ? as you have already read this ENERGY MASS CANT BE CREATED OR DESTROYED. In this scenario the energy is being transferred by the football player into the ball which appears as the kinetic energy of the ball... that's how it works
The Richter Scale<span> is not commonly </span>used<span> anymore, except for small </span>earthquakes<span>recorded locally, for which ML and Mblg are the only </span>magnitudes<span> that can be measured. For all other </span>earthquakes<span>, the </span>moment magnitude scale<span> is a more accurate measure of the </span>earthquake<span> size.</span>
Answer:
The net force applied to the car is zero.
Explanation:
We are given that a car is moving to the left with constant velocity.
When the car moving with constant velocity
Then, the final velocity=Initial velocity
Change in velocity=Final velocity- initial velocity=0
When change in velocity is zero then , acceleration of car
When acceleration is zero then, By Newtons second law
The net force applied on the car will be zero.
Option C:The net force applied to the car is zero.
The final velocity of the projectile when it strikes the ground below is 198.51 m/s.
<h3>
Time of motion of the projectile</h3>
The time taken for the projectile to fall to the ground is calculated as follows;
h = vt + ¹/₂gt²
where;
- h is height of the cliff
- v is velocity
- t is time of motion
265 = (185 x sin45)t + (0.5)(9.8)t²
265 = 130.8t + 4.9t²
4.9t² + 130.8t - 265 = 0
solve the quadratic equation using formula method,
t = 1.89 s
<h3>Final velocity of the projectile</h3>
vyf = vyi + gt
where;
- vyf is the final vertical velocity
- vyi is initial vertical velocity
vyf = (185 x sin45) + (9.8 x 1.89)
vyf = 149.322 m/s
vxf = vxi
where;
- vxf is the final horizontal velocity
- vxi is the initial horizontal velocity
vxf = 185 x cos(45)
vxf = 130.8 m/s
vf = √(vyf² + vxf²)
where;
- vf is the speed of the projectile when it strikes the ground below
vf = √(149.322² + 130.8²)
vf = 198.51 m/s
Learn more about final velocity here: brainly.com/question/6504879
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