Answer:
Elements are made up of only one type of atom. Each element has a unique chemical symbol. Elements can be identified by their atomic number.
Answer:
3 seconds
Explanation:
To solve this problem, we have to find the acceleration of the car.
Acceleration is given as:
a = (v - u) / t
Where v = final velocity
u = initial velocity
t = time taken.
From the question,
u = 0 m/s
v = 31 mph = 13.86 m/s
t = 1.5 seconds
Acceleration, a, will be:
a (13.86 - 0) / 1.5
a = 13.86 / 1.5
a = 9.24 m/s²
We are told that this kind of car operates with constant force. This means it operates with constant acceleration (since force and acceleration are directly proportional)
Therefore, when the final velocity of the car is 62 mph (27.72 m/s), time taken is:
a = (v - u) / t
=> t = (v - u) / a
t = (27.72 - 0) / 9.24
t = 3 seconds
It will take the car 5 seconds to go from zero to 62 mph.
<span>It also doubles
The gravitational force between two masses is expressed as:
F = G*m1*m2/r^2
where
F = Force between the two masses
m1 = Mass of object 1
m2 = Mass of object 2
r = distance between centers of object 1 and object 2
G = Gravitational constant
The exact values of G, m1, m2, and r don't matter since all except for m1 is held constant. And when m1 suddenly doubles, the force attracting the two object to each other also doubles.</span>
Answer:
Explanation:
Q1 = +2.50 x 10^-5C and Q2 = -2.50 x 10^-5C, r = 0.50m, F=?
Using Coulomb's law:
F = 1/(4πE) x Q1 x Q2/ r^2
Where
k= 1/(4πE) = 9 x 10^9Nm2/C2
Therefore,
F = 9x 10^9 x 2.50 x 10^-5 x2.50 x
10^-5/. ( 0.5)^2
F= 5.625/ 0.25
F= 22.5N approximately
F= 23N.
To find the direction of the force: since Q1 is positive and Q2 is negative, the force along Q1 and Q2 is force of attraction.
Hence To = 23N, attractive. C ans.
Thanks.
