Answer: This isn't a question but the statement is quite accurate to a well thought out science lesson.
a) time, t = 11.407 s, b) distance x = 175.66 m, v = c) speed v = 30.80 m / s
<h3>Explanation of question:</h3>
a) This is kinematics exercise, write the equation of each vehicle car is;-
x = x₀ + v₀ t + ½ a t²
Let's fix our the reference system at a point where the car indicate that the car stops from rest is vo = 0.
x₀ = v₀ = 0
<h3>we substitute</h3>
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
At the point where they are, positions are equal:-
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 20 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.0 11.407
v = 30.80 m / s
To know more about acceleration visit:-
brainly.com/question/12550364
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The answer is 60%. If you divide the 9 and 5, you will get 0.6. So you just move the decimal point to the right twice. (:
Answer: dv/dt = 0
Explanation: Acceleration has to do with when you are changing velocity. since velocity is a speed and a direction you only accelerate when you change speed or change direction or change both in other words you are not accelerating when you are moving in a constant speed and at a specified direction. E.g driving Eastward at a constant speed of 24m/s, such scenario is a case of not accelerating that is acceleration is zero.
