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3 years ago

What’s 21 divided by 4,314

Mathematics

2 answers:

Oliga [24]3 years ago

7 0

0.00486787204

Is the exact answer if you need to round then it’s different

sweet-ann [11.9K]3 years ago

4 0

21 divided by 4,314 is 0.00486787.
4,314 divided by 21 is 205.428571.

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There are some Chicken and rabbits in a cage. There are 20 heads and 62 feet in total, the question is: how many chicken and rab

horsena [70]

Answer:There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?

Step-by-step explanation

There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?

Legs of a chicken = 2

Legs of a rabbit = 4

Total heads = 72

Total legs= 200

Let's assume that each of them has minimum 2 legs.

So 72*2 = 144 legs

Remaining legs: 200-144= 56

These remaining legs belong to rabbit because rabbit has 4 legs each.

2*Rabbits= 56

Rabbits= 56/2 = 28

Out of 72, 28 are rabbits. So there are 72-28= 44 chicken.

5 0

2 years ago

PLEASE HELLP 25 POINTS

gayaneshka [121]

Hello from MrBillDoesMath!

Answer:

a^6 + 4 a^5 + 5 a^4 - 5 a^2 - 4 a - 1

Discussion:

You may need to clean things up a bit but suppose that

S(1) = a-1

S(2) = a^2 -1

Since this is a geometric series, the geometric ratio is given by

S(2)/ S(1) = (a^2 -1)/ (a-1)

= (a+1)(a-1)/ (a-1)

= a+1

Conclusion:

S(2) = (a+1) S(1) = (a+1) (a-1)

S(3) = (a+1) S(2) = (a+1) (a+1) (a-1) = (a+1)^ (3-1) (a-1)

S(4) = (a+1) S(3) = (a+1) * (a+1)^2 (a-1) ) = (a+1)^(4-1) (a-1)

in general.....

S(n) = (a+1)^ (n-1) (a-1)

S(6) = (a+1)^ (6-1) (a-1)

= (a-1) (a+1) ^ 5

= a^6 + 4 a^5 + 5 a^4 - 5 a^2 - 4 a - 1

Hope I didn't screw something here!

Thank you,

MrB

5 0

3 years ago

Read 2 more answers

Of 575 broiler chickens purchased from various kinds of food stores in different regions of a country and tested for types of ba

chubhunter [2.5K]

Answer:

a) $0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630$

$0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730$

And the 99% confidence interval would be given (0.630;0.730).

b) We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

c) For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval are satisfied, so then the results can be assumed for all the population

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p =0.68$ represent the estimated proportion

n=575 is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630$

$0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730$

And the 99% confidence interval would be given (0.630;0.730).

Part b

We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

Part c

For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval are satisfied, so then the results can be assumed for all the population

4 0

3 years ago

a flour company in minneapolis wants to know what percent of local households bake at least twice a week. A company representati

seropon [69]

Answer:

Step-by-step explanation:

The response of this would be to say that those people without daytime jobs that are outside the home, are more likely to be home and thus, have more time on their hands to attempt to bake. So basically, the quoted 56% is definitely going to be higher than the population percentage.

8 0

3 years ago

Monique made several batches of soup for a potluck supper. Each batch required 3\4 0f a pound of potatoes, and she used a total

eimsori [14]

Answer:

$The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.$