A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t) = 40t − 5t2, where x and y are in meters and the time t is in seconds. What is the ratio of y to x at time t = 5 seconds?
1 answer:
x(t) = 20t
y(t) = 40t - 5t^2
Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y
x(5) = 20(5) becomes x ( 5 ) = 1 0 0
y(5) = 40(5) - 5(5)^2 becomes y(5) = 200 - 125 and then y ( 5 ) = 7 5
The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 7 5 / 1 0 0 or 0.7 5
Answer : 0.75
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Answer would be the second one
A U B = B
