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3 years ago

Using the given postulate, tell which parts of the pair of triangles should be shown congruent.

Mathematics

1 answer:

weqwewe [10]3 years ago

4 0

Answer:

it should be the 5th one because it shows defencicy

Step-by-step explanation:

from what i know

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Solve for q. a=qb+r What is q equal to? q=a−r−b q=a−r/b q=a/b −r q=a/rb

Mademuasel [1]

The given equation is $a=qb+r$

We need to solve the equation for q.

Value of q:

The value of q can be determined by solving the equation $a=qb+r$ for q.

Thus, subtracting both sides of the equation by r, we get;

$a-r=qb$

Now, dividing both sides of the equation by b, we have;

$\frac{a-r}{b}=\frac{qb}{b}$

Simplifying the terms, we get;

$\frac{a-r}{b}=q$

Therefore, the value of q is $q=\frac{a-r}{b}$

Hence, Option B is the correct answer.

7 0

3 years ago

Warm up. help please

vampirchik [111]

Exponents are similar in concept to multipication. Multiplication is repeated addition and exponents are repeated multiplication.
So x^3 = x*x*x
f(-2) = (-2)(-2)(-2) = -8
Try the others For yourself!

3 0

3 years ago

I need help on my homework

soldi70 [24.7K]

Answer:

$\displaystyle m\angle AED=32.5^\circ$

Step-by-step explanation:

Angles in a Circle

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

$\displaystyle m\angle AED=\frac{AD-BC}{2}$

$\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}$

$\displaystyle m\angle AED=32.5^\circ$

8 0

3 years ago

Which Two Numbers Add Up To Negative 26 And Multiply To 11?

Fynjy0 [20]

Xy=11
x+y=-26

x+y=-26
minus x both sides
y=-26-x

sub for y
x(-26-x)=11
-26x-x^2=11
add 26x+x^2 both sides
x^2+26x+11=0

ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

a=1
b=26
c=11

x= $\frac{-26+/-\sqrt{26^{2}-4(1)(11)} }{2(1)}$
x= $\frac{-26+/-\sqrt{676-44} }{2}$
x= $\frac{-26+/-\sqrt{632} }{2}$
x= $\frac{-26+/-2\sqrt{158} }{2}$
x= $-13+/-\sqrt{158}$

x= $-13+\sqrt{158}$ or $-13-\sqrt{158}$

aprox

x=-0.420195 or -25.5698

those are the numbers

5 0

3 years ago

Please help whats a,h,k??

harina [27]

9514 1404 393

Answer:

a = -2, h = 2, k = 1

Step-by-step explanation:

Compare the expressions. Match one pattern to the other.

$f(x)=-2|x-2|+1\\\\f(x)=\ \,\,a|x-h|+k \qquad\ a=-2,\ h=2,\ k=1$

The transformations are ...

Translation by (h, k) = (2, 1). That is, 2 units right and 1 unit up.

Vertical scaling by "a", which is (i) reflection over the x-axis (because a < 0), and (ii) expansion by a factor of 2.

A table and graph are shown in the attachment.

5 0

3 years ago