Answer:


Step-by-step explanation:
<h3>Question-1:</h3>
so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,
to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

to solve the equation can consider the quadratic formula given by

so let our a,b and c be -4.9,229 and 346 Thus substitute:

remove parentheses:

simplify square:

simplify multiplication:

simplify Substraction:

by simplifying we acquire:

since time can't be negative

hence,
at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs
<h3>Question-2:</h3>
to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

let a and b be -4.9 and 229 respectively thus substitute:

simplify which yields:

now plug in the maximum t to the function:

simplify:

hence,
about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?
900 is the answer of 2 squared times 15 squared
The answer is A becaues 119 thousand times 10 equals 1190000
then you divide it by 100 to get A.119 hunderths
Answer:
975%
Step-by-step explanation:
468/48 - 9.75
9.75 in percent form is 9.75*100=975%
Too much for a Mariners jersey if you ask me :D
Answer:
16
Step-by-step explanation:
1. Use a vertical number line to count how many spaces are between -6 and 10.