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Rufina [12.5K]
3 years ago
6

Objects 1 and 2 attract each other with an electrostatic force of 18 units. If the charge of Object 2 is increased by a factor o

f 3 AND the distance separating Objects 1 and 2 is increased by a factor of 3, then the new electrostatic force will be _____ units.
Physics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

F'=18/3=6\ units

Explanation:

<u>Electrostatic Force </u>

We know particles 1 and 2 attract each other with an electrostatic force of 18 units. The force between two charged particles is given by Coulomb's formula

\displaystyle F=\frac{k\ q_1\ q_2}{r^2}

Where q_1,\ q_2 are the charges and r is the distance between them.

We are told the new charge 2 is

q_2'=3q_2

And the distance is three times the original

d'=3d

The new force is

\displaystyle F'=\frac{k\ q_1\ (3q_2)}{(3r)^2}

Operating

\displaystyle F'=\frac{3k\ q_1\ q_2}{9r^2}

\displaystyle F'=\frac{k\ q_1\ q_2}{3r^2}

This force is one third of the other one, so  

\boxed{F'=18/3=6\ units}

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