Answer:
Explanation:
Consider two particles are initially at rest.
Therefore,
the kinetic energy of the particles is zero.
That initial K.E. = 0
The relative velocity with which both the particles are approaching each other is Δv and their reduced masses are
now, since both the masses have mass m
therefore,
= m/2
The final K.E. of the particles is
Distance between two particles is d and the gravitational potential energy between them is given by
By law of conservation of energy we have
Now plugging the values we get
This the required relation between G,m and d
Answer:
The velocities of each ball are
Explanation:
Using the conservation of momentum to find the velocity of each balls after the collision
Here have one equation but have two variable don't know so
Now have two equations and two variables so solving using
Answer:
0.256 m/s
Explanation:
Speed is distance over time.
Find the speed of each trial and then find the average.
Trial 1: v = 0.7 m / 2.5 s = 0.280 m/s
Trial 2: v = 0.7 m / 2.75 s = 0.255 m/s
Trial 3: v = 0.7 m / 2.98 s = 0.235 m/s
v_avg = (0.280 m/s + 0.255 m/s + 0.235 m/s) / 3
v_avg = 0.256 m/s
Round as needed.
Answer:
The voltage is 2.114 V.
Explanation:
Given that,
Mass of both weights = 225 gm
Transducer sensitivity = 0.5 V/N
The first mass is located 20∘ north of east, the second mass is located 20∘ south of east,
We need to calculate the net equivalent force
Using formula of force
Put the value into the formula
We need to calculate the voltage
Using formula of voltage
Put the value into the formula
Hence, The voltage is 2.114 V.