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sveticcg [70]
3 years ago
9

Which activity is the best example of cardiovascular and strength training exercises work together

Physics
2 answers:
Nataly [62]3 years ago
4 0

it got to be jumping jacks that all i got

Natasha2012 [34]3 years ago
3 0

Answer:

<h2>Construction tasks.</h2>

Explanation:

A common activities where cardiovascular and strength training are together is during Construction tasks. In this context, aerobic and anaerobic exercises are present.

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1. A ball falls from a height "h" from a tower. Which of the following statements is true?
Strike441 [17]

Answer:

the total kinetic and potential energy of the ball is constant (mechanical energy remains the same)

Explanation:

As the ball falls, kinetic energy is increased in direct relation with the decrease in potential energy

ΔKE + ΔPE = 0

4 0
3 years ago
1. What is the kinetic energy of a 94 kg basketball player running at 7.3 m/s?
LUCKY_DIMON [66]
1. 2504.63 J

2. 929.5m/s

Hope this helps :)

I can explain it as well if you’d like
8 0
3 years ago
When water in a lake freezes, the ice that forms floats on top of any water that is still liquid. Why does the ice float?
ddd [48]

Answer:

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5 0
3 years ago
PLz I Need Help PLZZZ ASAP
AURORKA [14]

#1

As we are increasing the frequency in the simulation the wavelength is decreasing

So if speed remains constant then wavelength and frequency depends inversely on each other

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#2

As we are changing the amplitude in the simulation there is no change in the speed frequency and wavelength.

So amplitude is independent of all these parameter

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So light of greater intensity is the light of larger amplitude

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3 0
3 years ago
A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica
guajiro [1.7K]

Answer:

f_{e} = 1.7 cm

Explanation:

The magnification of the compound microscope is given by the product of the magnification of each lens

        M = M₀ m_{e}

        M = - L/f₀  25/f_{e}

Where f₀ and f_{e} are the focal lengths of the lens and eyepiece, respectively, all values ​​in centimeters

In this exercise they give us the magnification (M = 400X), the focal length of the lens (f₀ = 0.6 cm), the distance of the tube (L = 16 cm), let's look for the focal length of the eyepiece (f_{e})

         f_{e} = - L / f₀ 25 / M

Let's calculate

        f_{e} = - 16 / 0.6 25 / (-400)

        f_{e} = 1.67 cm

The minus sign in the magnification is because the image is inverted.

          f_{e} = 1.7 cm

6 0
3 years ago
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