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GalinKa [24]
3 years ago
6

Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the g

raph of the following inequality: y > one half x + 2
A) The origin is not included in the shaded region and the shaded area is above the line.
B) The origin is not included in the shaded region and the shaded area is below the line.
C) The origin is included in the shaded region and the shaded area is above the line.
D) The origin is included in the shaded region and the shaded area is below the line.
Mathematics
2 answers:
Scilla [17]3 years ago
5 0
The correct answer is C! Hope this helps!
lakkis [162]3 years ago
4 0
I think it is <span>C) The origin is included in the shaded region and the shaded area is above the line. </span>
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7.
snow_tiger [21]

Answer:

Range is 18.

Step-by-step explanation:

Range can be calculated by subtracting the smallest value of the data set from the largest value of the data set.

The values are:

13, 17, 18, 15, 12, 21, 10, 6, 8, 11, 3

Largest Value in this data set:  21

Smallest Value in this data set: 3

Range = Largest Value - Smallest Value

Range = 21 - 3

Range = 18

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Find the area of the shaded region. Round to the nearest tenth.
drek231 [11]

pi·18.6^2·123°/360° - 1/2·18.6^2·SIN(123°) = 226.3

8 0
3 years ago
A large envelope is 0.085 cm thick. How thick would a stack of 100 of these envelopes be? Explain your reasoning.
Pavlova-9 [17]

Answer:

8.5 cm

Step-by-step explanation:

I think because wouldn't you take the 0.085 · 100

(get mad if I'm wrong i might be)

3 0
3 years ago
Find the product -7/5(4/5)
katen-ka-za [31]

Answer:

-28/25 or -1 3/25

Step-by-step explanation:

Hope this helps

4 0
3 years ago
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