the vertices of ABC are points A(1,1), B(4,1), and C(4,5). find the cosines of the angles of the triangle.
2 answers:
Answer:
- cos(A) = 3/5
- cos(B) = 0
- cos(C) = 4/5
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relation between the cosine of an angle and the sides of the triangle.
Cos = Adjacent/Hypotenuse
__
<h3>Angle A</h3>In the given triangle, the hypotenuse is AC. The side adjacent to angle A is AB, so its cosine is ...
cos(A) = AB/AC
cos(A) = 3/5
__
<h3>Angle B</h3>The right angle in the triangle is angle B. The cosine of a right angle is 0.
cos(B) = 0
__
<h3>Angle C</h3>The side adjacent to angle C is CB, so its cosine is ...
cos(C) = CB/AC
cos(C) = 4/5
You might be interested in
Answer:
There is a 34.60% probability that 0 or 1 of them is nearsighted.
Step-by-step explanation:
For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem, we have that:
12% of children are nearsighted. This means that .
A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?
There are 18 students, so
This probability is:
So
So
There is a 34.60% probability that 0 or 1 of them is nearsighted.