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3 years ago

Could somebody simplify 75 for me?

1 answer:

7 0

We have to first find the largest square factor in the number that you are square rooting.
75
=
25
x
3
25
is a square number!
25
=
5
2
√
75
=
√
25
x
√
3
√
75
=
5
x
√
3
=
5
√
3
3 is a prime number and does not have any factors and thus the square root of 3 cannot be simplified further.

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Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0

3 years ago

Read 2 more answers

Determine the unknown side lengths’ to the nearest tenth. for the first question and also please help with question 6

Levart [38]

Answer:

z =15cm and

y=9.0cm

Step-by-step explanation:

Use sine rule

12/ sin53 = z / sin 90

Z = 12 x sin 90 / sin 53

Z = 15cm

To find y the angle opposite to y will be 180-(90+53)=37º

15/sin 90= y/sin37

y= 15 x sin37 /sin 90

y = 9.0cm

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3 years ago

Find an equation of the parabola y = ax2 + bx + c that passes through (0, 1) and is tangent to the line y = 4x − 4 at (1, 0).

larisa86 [58]

We are given the following:
- parabola passes to both (1,0) and (0,1)
 - slope at x = 1 is 4 from the equation of the tangent line 

First, we figure out the value of c or the y intercept, we use the second point (0, 1) and substitute to the equation of the parabola. When x = 0, y = 1. So, c should be equal to 1. The parabola is y = ax^2 + bx + 1 

Now, we can substitute the point (1,0) into the equation,
0 = a(1)^2 + b(1) + 1
0 = a + b + 1
a + b = -1 

The slope at x = 1 is equal to 4 which is equal to the first derivative of the equation.
We take the derivative of the equation ,
y = ax^2 + bx + 1
y' = 2ax + b

x = 1, y' = 2
4 = 2a(1) + b
4 = 2a + b 

So, we have two equations and two unknowns, 
2a + b = 4 
a + b = -1

Solving simultaneously,
a = 5 
b = -6

Therefore, the eqution of the parabola is y = 5x^2 - 6x + 1 .

6 0

2 years ago

Write an equation of a line that passes through the point (8,2) that is parallel and (b) perpendicular to the graph of the equat

oksian1 [2.3K]

For a parallel line the slope of the lines/equations will be the same but for perpendicular line the slope will be the negative reciprocal
-(1/4)*x+b
b=2-(-1/4)*8

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Oduvanchick [21]

Answer:

-3m+2/3. 2/3 is a fraction

Step-by-step explanation:

8 0

2 years ago