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Aleks [24]
3 years ago
12

Rearrange the equation to isolate A. H=K+log(A/C)

Mathematics
2 answers:
Maslowich3 years ago
4 0
H = K + log ( A/C )
log ( A/C ) = H - K
\frac{A}{C}= 10^{H-K}
A = C*10 ^{H-K}

 

Xelga [282]3 years ago
3 0

Answer:

A=C(10)^{H-K}

Step-by-step explanation:

The given equation is

H=K+\log(\frac{A}{C}

Subtract K to both sides of the equation

H-K=\log(\frac{A}{C}

Now, use the property, x=\log y\Rightarrow y=10^x

10^{H-K}=(\frac{A}{C}

Multiply both sides by C to isolate A

A=C(10)^{H-K}

The value of A is

A=C(10)^{H-K}

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