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mafiozo [28]
3 years ago
13

This bag has an unknown number of lollipops and jelly snakes in it. I know that Pr (jelly snake) = 4/5. How many jelly snakes co

uld I have in the bag, if I know I have over 10 lollies total?
Mathematics
1 answer:
juin [17]3 years ago
8 0

Answer:

40.

Step-by-step explanation:

Let J represent jelly snake.

Let L represent lollipops

Let S represent sample space

Let y represent the number of jelly snake in the bag. I.e

Number of J = y

Number of L = 10

Number of S = 10 + y

From the question given, we were told that the probability of jelly snake P(J) is 4/5.

But probability of jelly snake, P(J) is given by:

P(J) = nJ/nS

nJ = y

nS = 10 + y

P(J) = 4/5

Thu, we can obtain the number jelly snake, y, in the bag as follow:

P(J) = nJ/nS

4/5 = y/(10 + y)

Cross multiply

5y = 4(10 + y)

Clear bracket

5y = 40 + 4y

Collect like terms

5y – 4y = 40

y = 40

Therefore, the number of jelly snake in the bag is 40

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3 years ago
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deff fn [24]

Answer:

b = 12

Step-by-step explanation:

b/3 + 4 = 8

subtract 4 on both sides

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0.23 or 2.3% which is greater?
lisabon 2012 [21]

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0.23

Step-by-step explanation:

2.3% = 0.023

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Any questions feel free to ask. Thanks

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3 years ago
Emily buys a CD for $12.07,including tax. She gives the clerk a $20 bill. How many change should she receive?
soldi70 [24.7K]

Answer:

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Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se
kolbaska11 [484]

Answer:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

Step-by-step explanation:

Given:

The expression to expand is given as:

(x-3)(x-9)(x-4)

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

(a + b)(c + d) = ac + ad + bc + bd

(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)

Therefore, the equivalent expression after expanding is given as:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

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2 years ago
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