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3 years ago

Using the table below, how many cups of flour would you need to make 90 cookies?

Mathematics

2 answers:

Dovator [93]3 years ago

6 0

Answer:

60 : 4 :: 90 : c proportion

60c = 4(90) product means/extremes

60c = 360

c = 6

Or 90 is 1.5 times 60, therefore you need 1.5 times 4 cups.

Marysya12 [62]3 years ago

4 0

Answer:

4 cups

Step-by-step explanation:

cause I said so....

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3 years ago

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Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

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a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

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3 years ago

Which of following not a way to represent the solution of inequality 5(x + 2) GREATER THAN OR EQUAL TO 7x + 2(x − 1)?

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So because it says NOT a way....I think it's A...Maybe I'm wrong but whatever.

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3 years ago

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3 years ago

On the checkerboard, 4/10 of the pieces left are red. What fraction of the pieces left are black? Write the equation.

Alexeev081 [22]

Answer:

The fraction of black pieces left is $\frac{6}{10}$

Step-by-step explanation:

Given as :

On the checkerboard , The fraction of red pieces left = $\frac{4}{10}$

Let The fraction of black pieces left = x

So, The fraction of black pieces left = x = 1 - $\frac{4}{10}$

Or, x = $\frac{10-4}{10}$

Or, x = $\frac{6}{10}$

Hence The fraction of black pieces left is $\frac{6}{10}$ Answer

8 0

3 years ago

Using the table below, how many cups of flour would you need to make 90 cookies?​

Using the table below, how many cups of flour would you need to make 90 cookies?