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8090 [49]
2 years ago
10

tex-formula">
If 81 came out, what was dropped in?
I have rewritten the problem to 3^x=81 but do not know how to solve it.
Mathematics
2 answers:
kogti [31]2 years ago
5 0
It is good equation. Look, that:
81 = 3 x 3 x 3 x 3 = 3^4.
So you have to solve:
3^x = 3^4 
exponents have to be the same, so
x=4
That's mean that A(4) = 81

tia_tia [17]2 years ago
3 0
A(x)=3^x=81\\
3^x=81\\
3^x=3^4\\
x=4


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There are 12 such shapes. One can start with two squares, adding squares around the edge and rejecting shapes that have been previously seen. Repeating until you have 5 squares results in 12 distinct shapes.

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5 0
3 years ago
Halp me pls..<br> !!!!<br><br><br> :D I will be happy
pochemuha
The probability of multiple events happening is found by multiplying the probabilities of each event together.

P_{d+even\ number}=P_{d}*P_{even}\\\\P_{d}=\frac{number\ of\ events}{total\ number\ of\ events}=\frac{(d)}{a,\ b,\ c,\ d,\ e)}=\frac{1}{5}\\\\P_{even}=\frac{number\ of\ events}{total\ number\ of\ events}=\frac{(2,\ 4,\ 6)}{(1,\ 2,\ 3,\ 4,\ 5,\ 6)}=\frac{3}{6}=\frac{1}{2}\\\\\frac{1}{5}*\frac{1}{2}=\boxed{\frac{1}{10}}

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5 0
3 years ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
2 years ago
NEED HELP ASAP PLEASS AND THANK YOU ​
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7 0
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makkiz [27]
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2 years ago
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