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Katyanochek1 [597]
3 years ago
6

What represents 2 to the second power, 3 to the second power and five

Mathematics
2 answers:
Mkey [24]3 years ago
4 0
2x2=4
3x3=9
5x5=10
Because with powers it is the number times itself not the number times the power. So if i had 5 to the third power it would be 5x5x5=? 5x5=10x5=50 therefore 5 to the third power is 50
 I hope this helps!
kozerog [31]3 years ago
3 0

Answer:

2x2=4

3x3=9

5x5=10

Step-by-step explanation:

5x5=10x5=50 therefore 5 to the third power is 50

I hope this helps!

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Solve the following system of equations:<br> x + 3y = 9<br> x − 2y = 14
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X=14-2y
so, 14-2y+3y=9
y=1
x=14-2*1=12

Hope this answer can help you!
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--> 1618

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Multiple the following <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B15%7D%20%20%5Ctimes%20%20%5Cfrac%7B25%7D%7B12%
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5/2

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In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0 respectively. If the coefficient sk
RUDIKE [14]

Answer:

a) The third quartile Q₃ = 56.45

b) Variance \mathbf{ \sigma^2 =2633.31}

Step-by-step explanation:

Given that :

Q_1  =  30.8

Median Q_2 =  48.5

Mean  = 42

a) The mean is less than median; thus the expression showing the coefficient of skewness is given by the formula :

SK = \dfrac{Q_3+Q_1-2Q_2}{Q_3-Q_1}

-0.38 = \dfrac{Q_3+30.8-2(48.5)}{Q_3-30.8}

-0.38Q_3  + 11.704  =  Q_3  +30.8  - 97

1.38Q_3  =  77.904

Divide both sides by 1.38

Q_3 = 56.45

b) The objective here is to determine the approximate value of the variance;

Using the relation

SK_p = \dfrac{Mean- (3*Median-2 *Mean) }{\sigma}

-0.38= \dfrac{42- (3 *48.5-2*42) }{\sigma}

-0.38= \dfrac{(-19.5) }{\sigma}

-0.38* \sigma = {(-19.5) }{}

\sigma =\dfrac {(-19.5) }{-0.38 }

\sigma =51.32

Variance =  \sigma^2 =51.32^2

\mathbf{ \sigma^2 =2633.31}

7 0
4 years ago
What statement is true for the equation 3x - 3x - 2 = -2
Daniel [21]

Answer:

Infinitely many solutions

Step-by-step explanation:

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-2 = -2 Which is true, meaning it can be infinitely many solutions

8 0
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