X - 3 < 9 or x + 5 ≥ 10
+ 3 + 3 - 5 - 5
x < 12 or x ≥ 5
Solution Set: {x|x < 12 or x ≥ 5}, (-∞, 12) or (5, ∞)
Answer:
f(n) = -n^2 -3n +5
Step-by-step explanation:
Suppose the formula is ...
f(n) = an^2 +bn +c
Then we have ...
f(1) = 1 = a(1^2) +b(1) +c
f(2) = -5 = a(2^2) +b(2) +c
f(3) = -13 = a(3^2) +b(3) +c
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Here's a way to solve these equations.
Subtract the first equation from the second:
-6 = 3a +b . . . . . 4th equation
Subtract the second equation from the third:
-8 = 5a +b . . . . . 5th equation
Subtract the fourth equation from the fifth:
-2 = 2a
a = -1
Then substituting into the 4th equation to find b, we have ...
-6 = 3(-1) +b
-3 = b
and ...
1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation
5 = c
The formula is ...
f(n) = -n^2 -3n +5
Answer:
18
Step-by-step explanation:
Given the data:
180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg
The interquartile range (IQR) = Q3 - Q1
Reordering the data:
180, 188, 190, 192, 195, 200, 205, 209, 250
Q3 = 3/4(n+1)th term
Q3 = 3/4(10) = 7.5 th term = (205+209)/2 = 207
Q1 = 1/4(n+1)th term
Q1 = 1/4(10) = 2.5th term = (188+190)/2 = 189
Q3 - Q1 = 207 - 189 = 18
Answer:
8a+5b-9
Step-by-step explanation:
(8a+2b-4)+(3b-5)
8a+2b+3b-4-5
8a+5b-9
