PLEASE ANSWER QUICKLY! <br><br> Write an equation for each translation of y = |x|.<br> NUMBER 4

Find a counterexample to show that the statement is false. Assume all sets are subsets of a universal set U = {1, 2, 3, 4, 5}. (

natka813 [3]

Answer:

For subsets A={1,2},B={2,3},C={1,2 5} of U = {1, 2, 3, 4, 5}.

A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

Step-By-Step Explanation:

U = {1, 2, 3, 4, 5}.

A={1,2}

B={2,3}

C={1,2 5}

For the Left Hand Side

B-C={3}

A ∪ (B − C)= {1,2} ∪ {3} ={1,2,3}

Likewise, the Right Hand Side:

(A ∪ B)={1,2,3}

(A ∪ C)={1,2,5}

(A ∪ B)- (A ∪ C)= {1,2,3}-{1,2,5}={3}

Since, {1,2,3} ≠ {3}, A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

7 0

3 years ago

Which of the following relations is a function?

Mila [183]

Answer:

Option A

Step-by-step explanation:

A does not have an x that has 2 or more outputs

3 0

3 years ago

Read 2 more answers

Please answer this correctly

rjkz [21]

Answer:

6 and 4

Step-by-step explanation:

6 x 4 = 24

8 x 3 = 24

6+6+4+4 = 20

4 0

3 years ago

Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.

Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

$\frac{sinA}{a}=\frac{sinB}{b}$

$\frac{sin30}{4}=\frac{sinB}{6}$

$sinB=0.75$

$angle B = 48.6$

Another angle will be

$angle B' = 180-48.6 = 131.4$

considering angle B, angle C = $180 - (48.6+30)=101.4$

considering angle B', angle C' = $180-(131.4+30)=18.6$

$\frac{sinA}{a}=\frac{sinC}{c}$

$\frac{sin30}{4}=\frac{sin101.4}{c}$

$c = 7.84$

Similarly, finding c'

$\frac{sinA}{a}=\frac{sinC'}{c'}$

$\frac{sin30}{4}=\frac{sin18.6}{c'}$

$c'=2.55$

Hence two triangles are possible with below details: : Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

5 0

3 years ago

For the graph of the inequality x - 2y >4, what is a value of x for a point that is on the

Colt1911 [192]

Answer:

Step-by-step explanation:

Explanation:

First, find two points on the line if you change the inequality to an equation.

For

x

=

0

:

0

+

2

y

=

4

2

y

=

4

2

y

2

=

4

2

y

=

2

or

(

0

,

2

)

For

y

=

0

:

x

+

0

=

4

x

=

4

or

(

4

,

0

)

We can plot these two points and draw a line through them to get the border of the inequality:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)(x+2y-4)=0}

The line will be solid because the inequality operator has a "or equal to" clause in it. We can now shade the area to the right of the line because the inequality has a "great than" clause in it.

graph{(x+2y-4)>=0}

4 0

3 years ago

PLEASE ANSWER QUICKLY! Write an equation for each translation of y = |x|. NUMBER 4