3 years ago

Determine if (-2,5) is a solution of Of 3x+4y=14

Mathematics

1 answer:

Serggg [28]3 years ago

8 0

Well that's easy. Just plug in the numbers: 3*(-2)+4*(5)=14. So yes the solution is correct.

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The total charge on 8 particles is −56 units. All the particles have the same charge.

kirza4 [7]

You have to divide negative fifty-six by eight to get the charge on each particle. So you do -56/8. Which gives you negative seven as the answer.
Answer = -7

5 0

3 years ago

if a class of 20 students 40% are boys. twenty-five percent often boys and 50% of the girls wear glasses. how many students wear

shtirl [24]

2 boys and 6 girls wear glasses, so 8 students wear glasses

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2 years ago

2×-6=12

Svet_ta [14]

Answer:

2 multiply by six is 12

Step-by-step explanation:

this answer is not correct

the answer would be -12 as the biggest no. is 6 and it contains - sign

hope it helps you pls mark me as brainlest

if not possible the just thank and vote

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3 years ago

When do we use the addition and subtraction formulas for sine or cosine?

777dan777 [17]

When we need the cosine of the sum of two angles, we use the addition formula for cosine.

When we need the sine of the difference of two angles, we use the difference formula for sine.

Let's try one. Say we needed to know

$\cos 15^\circ
$

We're only expected to know the trig functions of 30/60/90 and 45/45/90 triangles. Fortunately, $15^\circ = 45^\circ - 30^\circ$ so

$\cos 15^\circ = \cos( 45^\circ - 30^\circ )$

$= \cos( 45^\circ) \cos(30^\circ ) + \sin(45^\circ) \sin(30^\circ)$

$= \dfrac{\sqrt{2}}{2} \cdot \dfrac{ \sqrt{3}}{2} + \dfrac{\sqrt{2}}{2} \cdot \dfrac{1}{2}$

$\cos 15^\circ = \frac{1}{4} (\sqrt{6} + \sqrt{2})$

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3 years ago

the school has 48 students on the football team 18 of them are freshman what percent are upper classmen

valentinak56 [21]

62.5%
Subtract 18 from 48 and get 30. Then you divide 30/48

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3 years ago