The correct answer is C.
The limit in A does exist:
The limit in B also exists: for any ,
But this alone does not prove the 2D limit exists. only captures all the paths through the origin that are straight lines.
The limit in C also exists, but it's not the same as either of the limits along the paths used in A and B.
That this value is non-zero tells us the original limit does not exist.
The claim in D is generally not correct. That is undefined does not automatically mean the limit doesn't exist. A simpler example:
yet is undefined.
Cos²x+2cos x+1=0
We have to do a change of variable.
cos x=t
Then, we have the next square equation.
t²+2t+1=0
We solve this square equation:
t=[-2⁺₋√(4-4)]/2=-1
if cos x=t then we have that:
cos x=-1
x=cos⁻¹ -1= π radians or 180º.
Answer: x=π (in radians) or x=180º (in degrees).
Answer:
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Step-by-step explanation:
Just did the quiz. First one is "a + b"
Second spot put "a+b/2"
Third put "c/2"
Finally put "CE" and then "BE"
Question:
The recursive function , represents the nth term of a sequence. Determine the explicit function
Answer:
Step-by-step explanation:
Given
Required
Write an explicit formula
Let n = 1
Let n = 2
Let n =3
Let n = 4
So, we have:
Following the above pattern:
Open bracket