The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Answer:
sorry
Step-by-step explanation:
Answer:
1.875 Pounds
Step-by-step explanation:
Answer:
1312.5 cubic feet
Step-by-step explanation:
Let the swimming pool be a rectangular prism
The volume of a rectangular prism is:
Volume = length * width * depth
Length = 25 (given)
Width = 15 (given)
The depth is 4ft, but they want the volume when water is 6 inches FROM THE TOP, that is, out of 4 feet, 6 inches (1/2 feet) IS NOT FILLED. So the depth of water is
4 - 1/2 = 3.5 feet
So, we can say
Depth = 3.5 (found)
Hence, the volume would be:
Volume = 25 * 15 * 3.5 = 1312.5 cubic feet
Tell you the truth bro I don't know
