Step-by-step explanation:
1)y=17-2=15
2)y=17-6=11
3)y=17-8=9
4y=17-10=7
Answer:
A: 500 square feet
Step-by-step explanation:
A: First you have to draw a grid.
You plot the points A,B, and C.
The fourth point would be -5,25 because it matches with the points.
You make a rectangle out of those points
Points AB is 2 feet. Since the interval I used was 5 I would multiply 2 by 5 to get 10.
Then I would find Points BC which is 10 feet. Again multiply it by 5 to get 50.
50 x 10 is 500.
B: Jenna has to reflect over the y-axis. This is because the y-axis is between Quadrants II and I. When reflecting over the y-axis the y-coordinate stays the same but the x-coordinate switches to it's opposite. Basically the x-coordinate is negative in Quadrant II, but in when reflecting over the y-axis the x-coordinate would change to a positive in Quadrant I. So if the point in Quadrant II looks like this: (-X,Y) then when reflecting over the y-axis to Quadrant I would look like this: (X,Y).
Lets see the answer to this question the fraction of the entire load of dirt in each mound is b.1/2 this is how i got my answer you multiply 3*1/6=1/2 so the fraction of the entire load of dirt that was in each mound is 1/2
Answer:
D. ∠E ≅ ∠N
Step-by-step explanation:
The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...
∠E ≅ ∠N
Then the SAS congruence postulate can be claimed.
__
<em>Additional comment</em>
The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.
Answer:
(3x/4) + 4
Step-by-step explanation:
convert al to decimal and then add
1.25 + 0.75 +0 .4 + 2x 0.375 + 1.6