Solve the following using order of operations a.4+5(2)

If times AB and CB are parallel, then angels c and e are

REY [17]

A

because c and g are same and g and e are complementary.

5 0

3 years ago

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Angle T had a measure between 0 and 360 and is coterminal with -170 angle. What is the measure of angle T?

Alika [10]

Answer: The answer is 190°.

Step-by-step explanation: We are to find the measure of ∠T which lies between 0° and 360° and is co-terminal with an angle of measure -170°.

We know that two angles are said to be co-terminal if one is obtained from the other by either adding or subtracting 360°.

So, angles which are co-terminal with -170° are

-170° + 360° = 190°, -170° - 360° = 530°, etc.

Since 190° lies between 0° and 360°, so measure of ∠T is 190°.

Thus, the answer is 190°.

5 0

3 years ago

What will be the value of

madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

$\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}$

Then you want to know the value of

$\displaystyle\lim_{n\to\infty}a_n$

if it exists.

To show the limit exists and that $a_n$ converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that $a_1=\sqrt{42}\le\sqrt{49}=7$ . Suppose $a_k\le 7$ . Then $a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7$ . So by induction, $a_n$ is bounded above by 7 for all $n$ .

Monontonicity: We have $a_1=\sqrt{42}$ and $a_2=\sqrt{42+\sqrt{42}}$ . It should be quite clear that $a_2>a_1$ . Suppose $a_k>a_{k-1}$ . Then $a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k$ . So by induction, $a_n$ is monotonically increasing.

Then because $a_n$ is bounded above and strictly increasing, the limit exists. Call it $L$ . Now,

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L$

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}$

$\implies L=\sqrt{42+L}$

Solve for $L$ :

$L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7$

We omit $L=-6$ because our analysis above showed that $L$ must be positive.

So the value of the infinitely nested radical is 7.

4 0

3 years ago

Which postulate proves the two

Vanyuwa [196]

Answer:

D. none

Step-by-step explanation:

The figure shows two triangles. We see a right angle in each triangle. All right angles are congruent. One angle of one triangle is congruent to one angle of the other triangle. We are not given any other information about congruent sides or other congruent angles. Therefore, there is not enough information to prove the triangles are congruent.

Answer: none

8 0

3 years ago

How can x+8=-x+7 be set up as a system of equations A. Y=x+8 Y=-x+7 B. y=x+8 Y=-3x+7 C. Y=x+5 Y=-2x+11 D. Y=8 Y=-3x+7

ch4aika [34]

X + 8 = -x + 7

it can be set up like this :
y = x + 8
y = -x + 7

8 0

4 years ago

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