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Stells [14]
3 years ago
8

Alina is able to swim at a rate of about 2.5 miles per hour. Talia is able to swim at a rate of 1.8 meters per second. Which sta

tement comparing the two swimmers is accurate?
1 mile 1,609 meters
Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

1 mile = 1,609 meters is the key to converting the rates of the two swimmers

Step-by-step explanation:

there are 60 seconds in a minute and 60 minutes in an hour

so 1.8 meters/sec x 60 sec/min x 60 min/hr = 6480 meters/hr

now we convert meters to miles

6480 meters/1 hr x 1 mile/1609 meters = roughly 4 miles/hr (4.027)

or we can convert the other rate to meters/sec

2.5 mi/hr x 1hr/60 min x 1min/60 sec = 0.00069444 mi/sec

then convert miles to meters

0.00069444 mi/sec x 1609meters/ 1mi = roughly 1.1 meters/sec (1.117)

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Step-by-step explanation:

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A summarine is only allowed to change his depth by rising Toward the surface in 50 m stages it starts off at negative 235 m how
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Answer:

It will take 5 stages to reach the surface.

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3 years ago
A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the
zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power =  1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

d = \frac{1}{2} ({v-0})t

5.5= \frac{1}{2} (1.6v)

The speed of the sprinter then become:

v = 6.875 m/s

Part (b)

Convert the weight of the sprinter to mass:

m = \frac{w}{g}

m = \frac{706}{9.8}

m = 72 kg

KE (Kinetic Energy) can then be calculated as:

KE = \frac{1}{2} mv^{2}

KE = \frac{1}{2} (72)(6.875)^{2}

KE = 1701.56 J = 1.70 kJ

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

P = \frac{KE}{t} \\\

P = \frac{1701.56}{1.6}

P = 1063.48 W = 1.06 kW

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The series 6 + 6 + 6+ 6 + 6 +
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