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3 years ago

8

Alina is able to swim at a rate of about 2.5 miles per hour. Talia is able to swim at a rate of 1.8 meters per second. Which sta

tement comparing the two swimmers is accurate?
1 mile 1,609 meters

1 answer:

bonufazy [111]3 years ago

5 0

Answer:

1 mile = 1,609 meters is the key to converting the rates of the two swimmers

Step-by-step explanation:

there are 60 seconds in a minute and 60 minutes in an hour

so 1.8 meters/sec x 60 sec/min x 60 min/hr = 6480 meters/hr

now we convert meters to miles

6480 meters/1 hr x 1 mile/1609 meters = roughly 4 miles/hr (4.027)

or we can convert the other rate to meters/sec

2.5 mi/hr x 1hr/60 min x 1min/60 sec = 0.00069444 mi/sec

then convert miles to meters

0.00069444 mi/sec x 1609meters/ 1mi = roughly 1.1 meters/sec (1.117)

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If the graph of the quadratic parent function q(x) = x2 is translated 3 units to the right and 2 units down, which of the follow

ludmilkaskok [199]

Answer:

s(x) = (x - 3)^2 - 2

Step-by-step explanation:

q(x) = x^2 becomes r(x) = (x - 3)^2 after a 3-units-to-the-right translation.

This, in turn, becomes s(x) = (x - 3)^2 - 2, after a 2-units-down translation.

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4 0

2 years ago

Kendra buy a magazine for $3 and four paperback books for $5 each. The expression 3 + 4 x 5 represents the total cost in dollars

BARSIC [14]

3 is the total dollars 1 magazine cost
4 is the total of paperback books she bought
5 is the total dollars 1 paperback book cost
multiply 4 by 5 to get total cost of the 4 paperback books and add 3 of the total cost of the magazine to get the total cost of everything

8 0

3 years ago

3<br> x. 3x²+x-3=0<br> Find the zeros

Tanya [424]

Answer:

The zeroes of this polynomial are $x_{1} \approx 0.847$ and $x_{2} \approx -1.180$ .

Step-by-step explanation:

Let $3\cdot x^{2}+x - 3 = 0$ , the quickest and most efficient approach to find the zeroes of this second order polynomial is by Quadratic Formula. For all $a\cdot x^{2}+b\cdot x + c = 0$ , roots are determined by:

$x_{1,2} = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$ (1)

Where $a$ , $b$ , $c$ are coefficients of the polynomial.

If we know that $a = 3$ , $b = 1$ and $c = -3$ , then roots of the polynomial are, respectively:

$x_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (3)\cdot (-3)}}{2\cdot (3)}$

$x_{1,2} =\frac{-1\pm \sqrt{37}}{6}$

The zeroes of this polynomial are $x_{1} \approx 0.847$ and $x_{2} \approx -1.180$ .

3 0

2 years ago

Can Someone help me pleases. Marking brainiest

ELEN [110]

Hope these notes help ! https://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html

6 0

2 years ago

The function f(x) = 6x + 8 is transformed to function g through a horizontal stretch by a factor of 5. What is the equation of f

elixir [45]

Answer:

$g(x) = 30\cdot x +40$ ; $a \approx 1.898$ , $k = 40$ .

Step-by-step explanation:

The resultant function is obtained by multiplying $f(x)$ by a real number $k$ . That is:

$g(x) = k \cdot f (x)$

If $k = 5$ and $f(x) = 6\cdot x + 8$ , then $g(x)$ is:

$g(x) = 5\cdot (6\cdot x + 8)$

$g(x) = 30\cdot x +40$

Given that presence of the expression $g(x) = 6^{a}\cdot x + k$ , then:

$6^{a} = 30$ and $k = 40$

The value of a is obtained by applying the definition of logarithms:

$a = \log_{6}30$

$a \approx 1.898$

Finally, the value of k is found by direct comparison:

$k = 40$

6 0

3 years ago