Answer:
Step-by-step explanation:
To make the problem easier to solve, we will set it up as the equation of the length of time of each class times the number of classes equals the total amount of minutes. However, since we don't know the number of classes, we'll symbolize our two unknowns with two variables.
75x + 45y = 705
(75x + 45y)/15 = 705/15
5x + 3y = 47
y = (47-5x)/3
It looks like we can't simplify the equation any more, so now it is a matter of trial and error. The minimum number of Saturday classes means the maximum number of weekday classes. We first will test for the maximum by assuming there are no Saturday classes, then will work our way up until x is an integer.
If x = 0
(47-5(0))/3 = 47/3 = 15.6666
If x = 1
(47-5(1))/3 = 42/3 = 14
This works. Therefore, the maximum number of weekday classes is 14, or choice b.
9514 1404 393
Answer:
(b) 9
Step-by-step explanation:
The product of segment lengths to the near and far intersection with the circle is the same for both secants.
4(4+5) = 3(3+x) . . . . the above statement with numbers filled in
36 = 9 +3x . . . . . . . simplify
12 = 3 +x . . . . . . . . divide by 3
9 = x . . . . . . . . . . . subtract 3
Answer:
<h2>5n</h2>
Step-by-step explanation:
5, 10 ,15, 20
it is going up in 5
so 5n
Answer:
yes you're right :)
Step-by-step explanation:
you have to use the pythogram therom for this
a² + b² = c²
20² + 10² = c²
400 + 100 = c²
c = √500
Answer:
x = -6
Step-by-step explanation:
3x - 4 = 2x - 10
3x - 2x = -10 + 4
x = -6
