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Dmitry [639]
3 years ago
9

What do the following two equations represent?

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer:

perpendicular lines

Step-by-step explanation:

when the two equation are written in slope intercept form:

y = -4x -7

y = 1/4x -2

the slopes are opposite reciprocals which means they are perpendicular

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Which of these is equal to ⅔ × ¾ × ⅗?
Sphinxa [80]

Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers)  and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5  would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor.  I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers.  I will choose 3.  I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

7 0
2 years ago
Read 2 more answers
2cos2ysin2y<br>simplify​
murzikaleks [220]

Reorder 2 cos (2y) and sin (2y)

= sin (2y)(2 cos(2y))

Remove parenthesis

= sin (2y) * 2 cos (2y)

Reorder sin (2y) and 2

= 2 * sin (2y) cos (2y)

Apply the sine double-angle identity

= sin (2(2y))

Now multiply 2 by 2

<u>= sin (4y) </u>

8 0
3 years ago
Write a proportion that could be used to solve for each variable. Then solve.
iren [92.7K]
60/25 = 12/Y
cross multiply and divide

25 x 12 = 300 

300 / 60 = 5

Y = 5 boxes
4 0
3 years ago
Is 3/10 of the visitors were adults and there were 100 visitors how many visitors were adults?
e-lub [12.9K]
So, 3/10 = 100/x\frac{3}{10}= \frac{100}{x}  3x=100(10) 3x=1000 1000/3 = 333.33=x
5 0
3 years ago
Find the derivative of Y=2xcos2x​
Nastasia [14]

Answer:

Y' = -xsin(2x) + 2cos(2x)

Step-by-step explanation:

For this problem, we will need to use the product rule since you have two terms that contain the variable x.

The product rule is simply as follows:

The derivative of the function is the product of the first term times the derivative of the second term plus the derivative of the first term times the second term.

Note the derivative of 2x with respect to x, is 2.

Note the derivative of cos(2x) with respect to x is (-1/2) sin(2x).

With this in mind, let's find the derivative of our function with respect to x.

Y = 2xcos2x

Y = 2x * cos(2x)

Y' = 2x * (-1/2)sin(2x) + 2 * cos(2x)

Y' = (2x * -1 / 2) sin(2x) + 2 * cos(2x)

Y' = (-x)sin(2x) + 2cos(2x)

So the derivative of our function is Y' = -xsin(2x) + 2cos(2x) according to the application of the product rule.

Cheers.

3 0
3 years ago
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