<u>Answer-</u>
<u>Solution-</u>
The dimensions of the cuboid is, 80×80×140 cm
So, its volume will be 
cm³
The dimensions of the cylinder is, radius = 40cm, height = 70cm
So, its volume will be 
cm³
Total volume,
As we know,
Answer:
13 m
Step-by-step explanation:
The ladder forms a right triangle with the wall that has legs of 5 and 12. We need to solve for the length of the ladder, which in this case, is the hypotenuse of the right triangle. You could use the Pythagorean Theorem but there's an easier way to do this. We can use the 5 - 12 - 13 Pythagorean triple so we know that the length of the ladder is 13 m.
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
The avarage is 180:18=10 , 10 min per hole
