Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
B or 12 would be the correct choice!
Hope this helps and mark as brainliest please!
Y= 17 would be the answer.
For something to be a function, it needs an input (x) and an output (y).
There is no x is this answer.
I hope this helps!
~cupcake