Answer: the square root of 30 is simplified to 5...
Hope this helps! :D
Step-by-step explanation:
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Hello :
(3, 13) <span>pair - solution because when x=3 y = 5(3)-2 = 13</span>
Answer:
<h3>A≈974.83</h3><h3>V Volume </h3><h3>2862</h3><h3>
Step-by-step explanation:</h3>
<h3>Using the formulas</h3><h3>A=4πr2</h3><h3>V=4</h3><h3>3πr3</h3><h3>Solving forA</h3><h3>A=π⅓(6V)⅔=π⅓·(6·2862)⅔≈974.83372</h3>
<h3>brainliest pls and ur welcome</h3>