Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
x = 7
Step-by-step explanation:
Assuming the quadrilateral is a parallelogram, then the diagonals bisect each other.
7x - 8 = 41
7x = 49
x = 7
What are we supposed to be basing this off of? is there no additional information?
The answer is B... T'(0,0), S'(-1,2), R'(1,3), Q'(4,1)
Step-by-step explanation:
A- Equilateral (all of the angles are the same)
B- isosceles (just two angles are the same)
C- scalene (non of the angles are the same)