3 years ago

the length of a rectangular frame is 15 inches and the width of 8 inches. what is the length of a diagonal of this Fram inches

Mathematics

2 answers:

juin [17]3 years ago

5 0

Answer:

sorry just a sec

Step-by-step explanation:

maybe 9?

Rashid [163]3 years ago

4 0

Answer:

using the phytogaran theory we get 17 inch as the length of the diagonal

You might be interested in

Can someone explain how to do problems like <br> (-2+4) or (4+ -6)

KiRa [710]

Answer:

All you have to do is just add the numbers inside the parenthesis. (4+-2) is the same as 4-2 which is equal to 2. (4+-6) is the same as 4-6 which is equal to -2.

Step-by-step explanation:

If this has helped please mark as brainliest

4 0

3 years ago

Read 2 more answers

Find the volume for the problem

dolphi86 [110]

The answer is 523.6 yards squared

4 0

3 years ago

A 5-pound bag of cat food costs $11.25. What is the unit price of the cat food?

Montano1993 [528]

Answer:

C $2.25

Step-by-step explanation:

$11.25÷5=$2.25

3 0

3 years ago

Read 2 more answers

Suppose that an individual has a body fat percentage of 16.8% and weighs 152 pounds. How many pounds of his weight is made up of

Keith_Richards [23]

Answer:

25.5 pounds

Step-by-step explanation:

<u>16.8% of 152 pounds is:</u>

168*152/100 = 25.5 pounds (rounded)

3 0

3 years ago

Read 2 more answers

Despejar la variable <br> 2x al cuadrado + 15= 113

Rudik [331]

Hola!

x = 7 , x = -7

Explicación:

Comienza restando 15 en cada lado:

$2x^{2} + 15 -15=113-15$

Usted obtiene:

$2x^{2} =98$

Ahora divide ambos lados por 2:

$\frac{2x^{2} }{2} =\frac{98}{2}$

Usted obtiene:

$x^{2} =49$

Como la ecuación está al cuadrado, tendrás que hacer:

$x=\sqrt{f(a)} , x=-\sqrt{f(a)}$

que te da: $x=\sqrt{49} , x =-\sqrt{49}$

Entonces:

$\sqrt{49}=7 , -\sqrt{49} = -7$

6 0

3 years ago