Answer:
0.1151
Step-by-step explanation:
Given that a laptop company claims up to 10.1 hours of wireless web usage for its newest laptop battery life. However, reviews on this laptop shows many complaints about low battery life. A survey on battery life reported by customers shows that it follows a normal distribution with mean 9.5 hours and standard deviation 30 minutes.
If X is the battery life then X is N(9.5, 0.5)
(we convert into one unit for calculations purpose here hours)
a) the probability that the battery life is at least 10.1 hours
=
we get the probability that the battery life is at least 10.1 hours is 0.1151
Answer:
(-5, 9)
Step-by-step explanation:
(-3-2, 2+7)= (-5,9)
Answer:I believe this is a demonstartion of the communitive property the equation backwards is the right5 awnser
Step-by-step explanation:
X = measure of each of the legs
"perimeter is 8 more than 2 times one of the legs" ---> P = 2x+8
P = 28 is the given perimeter
So,
P = 2x+8
28 = 2x+8
2x+8 = 28
2x = 20
x = 10
If x = 10, then the two legs add up to x+x = 10+10 = 20
Leaving P-20 = 28-20 = 8 inches left over for the base
You have the correct answer (choice D, 8 inches) though your steps are a bit confusing at some parts. Such as the part where you wrote 2x = 10 twice. I think I know what you were trying to say.
Answer:
1. A. (3,-2)
2. D. (-4,3)
3. (4,-2)
4. B. 3 cars
5. B. -10x7y2
Step-by-Step Explanation:
1. Graph the problem next time and to solve it, you just write the point where the intersect.
2. Write the second equation into the first one by substituting the y with the second equation: -3x-3(-5x-17)=3
3. Tbh its easier to just graph this one too and find the intersect point.
4. After reading the problem you should come up with the equations 5x+45y=195 and x+y=7 with x representing the number of cars and y representing the number of buses. All you have to do is substitute them into each other like in problem 2.
5. Multiply 12 and -5/6, then multiply the variables x^4 with x^3 y^2. All you have to do is add the exponent numbers together.
