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3 years ago

Look at the triangle ABC. What length of side AB of the triangle? a.2 b.square root of 20 c.6 d.square root of 38

Mathematics

2 answers:

storchak [24]3 years ago

5 0

Hello!

To find our answer, we can use the Pythagorean Theorem. This is a²+b²=c², where a and b are the legs and c is the hypotenuse.

As you can see, AB is the hypotenuse. Therefore we just plug in values for a and b, or the other sides that are legs.

2²+4²=c²

4+16=c²

To find c, we undo our exponent by adding a square root to both sides.

c=√20

Therefore, our answer is B.

I hope this helps!

Y_Kistochka [10]3 years ago

4 0

I think is b cuz I know foe a fact;)

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All of the following are equivalent, except.

yulyashka [42]

Answer: B.

Step-by-step explanation: This is because you can't possibly have an exponent, there are no two of the same value being multiplied together.

5 0

2 years ago

PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the

drek231 [11]

Answer:

1) The height of the ball from 0 to 5 seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0

3 years ago

Which of the following is the solution to the following systems of inequalities? (picture included)

Ymorist [56]

Answer:

C. (see the attachment)

Step-by-step explanation:

Both inequalities include the "or equal to" case, so both boundary lines will be solid. That excludes choices A and D.

The first inequality is plotted the same way in all graphs, so we must look at the second inequality. The relationship of y and the comparison symbol is ...

-y ≥ (something)

If we multiply by -1, we get ...

y ≤ (something else)

This means the solution space will be on or below (less than or equal to) the boundary line. This is the shaded area in graph C. (Graph B shows shading above the line.)

___

Further comment

Since the boundary for the second inequality is fairly steep, "above" and "below" the line can be difficult to see. Rather, you can consider the relationship of x to the comparison symbol. For the second inequality, that is ...

x ≥ (something)

indicating the solution space is on or to the right of the boundary line.

3 0

3 years ago

In a bag of jellybeans there are 6 purple jellybeans, 5 blue jellybeans, 3 yellow jellybeans, 2 green jellybeans, and 4 red jell

ikadub [295]

Answer:

9/10

Step-by-step explanation:

There are 20 and 2 green 20-2 is 18 so 18/20 simplified is also 9/10

7 0

3 years ago

Read 2 more answers

Find anequation of the line containing (3,-4) and having slope -2. If this line

Stells [14]

Answer:

A linear equation can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we want to have a slope equal to -2, then our line will be something like:

y = -2*x + b

Now, we also want this line to pass through the point (3, -4)

This means that when x = 3, we must have y = -4

Then:

-4 = -2*(3) + b

-4 = -6 + b

-4 + 6 = b

2 = b

Then our line is:

y = -2*x + 2

Now, the second part says that:

If this line contains the points (2,8) and (5.b), find a and b.

This is incorrectly written because this line clearly does not contain the point (2, 8), so i guess the actual problem is something like:

If this line contains the points (a,8) and (5.b), find a and b.

If the line contains the point (a, 8), this means that when y = 8, we must have x = a.

Then:

8 = -2*a + 2

8 - 2 = -2*a

6 = -2*a

6/-2 = -3 = a

a = -3

Similar reasoing for the other point, if the line contains the point (5, b), this means that when x = 5, we have y = b.

Then:

b = -2*5 + 2 = -10 + 2

b = -8

7 0

3 years ago