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3 years ago

What is the length of a rectangle that is the perimeter of 114 units?

Mathematics

1 answer:

Simora [160]3 years ago

6 0

There are many answer as long as the length and width add up to 57.

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PLEASE ANSWER

Gekata [30.6K]

Answer:

The answer is C I believe

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the balanced equation for the reaction (NH4)2SO4+SrCl2-->

steposvetlana [31]

(NH4)2SO4+SrCl2--><span>(NH4)2Cl2 + SrSO4

The reaction side are both aquas and the product is aquas and a solid precipitate. </span>

7 0

3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

-2=12/x<br><br> pleasee answer

Alecsey [184]

Answer:

Step-by-step explanation:

6 0

2 years ago

85% of z is 106,250. What is z?

Lady bird [3.3K]

Answer:

z=12500

Step-by-step explanation:

Of means multiply and is means equals

85% *z = 106250

Change to decimal form

.85z = 106250

Divide each side by .85

.85z/.85 = 106250 /.85

z=12500

5 0

3 years ago

Read 2 more answers