The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
Answer:
PQ = 134.9 feet
Step-by-step explanation:
sin 46 = 97/PQ
0.7193 = 97/PQ
PQ = 134.85 feet
0.550×$60 = $33
$60- $33= $27.00
Therefore, the answer is $27
Answer:
8/5
Step-by-step explanation: