First we have to find the tangent line:
y - y o = f ` ( x o ) * ( x - x o )
f ` ( x ) = 10 x
y - 80 = 40 ( x - 4 )
y = 40 x - 160 + 80
y = 40 x - 80
There are 2 parts of this region:
A =
A = 40/3 + 320/3 - 320 + 320 - 40/3 + 80 - 160 = 320/3 - 240/3 =
80/3
The interior angles on the same side of the transversal are supplementary. If two parallel lines are cut by a transversal, the interior angles on the same side of the transversal are supplementary.
In the given triangle , Coordinates of A (-1,3) , B (-5,-1), C (3,-1).
Let's find the slope of AB and AC .
Formula of slope is
For AB, slope is,
And slope of AC is
Product of the slopes of AB and AC is
Since the product of the two slopes is -1, so AB and AC are perpendicular.
And if they are perpendicular, angle BAC is 90 degree, so the triangle is right triangle .
Now we check the length of the sides of the triangle, and for that we use distance formula , which is
So for AB,
For AC,
For BC,
And since two sides are equal, so the triangle is isosceles triangle .
Answer:
B. is the answer
Step-by-step explanation:
y>-3x+2
let's do one by one
A. Is 2>-3(-4)+2? negative times negative is positive so 2 is not greater than 12 +2 or 14
B. is 2>-3(4)+2? -3•4=-12 +2 =-10 so yes 2>-10
C. is -2>-3(-2)+2? negative •negative is positive 6+2=8 so -2 is not greater than 8
D. is 0>-3(-4)+2? -•-=+ so 12+2=14. so 0 is not greater than 14
8 verticals i’m pretty sure if not uh yea
