Please help me on number 3

Mathematics

1 answer:

stira [4]3 years ago

5 0

Percentage of bags on which coupons were placed
Monday - 24/120 × 100 = 20%
Tuesday - 32/130×100 =24.61≈ 25%
Wednesday - 38/155×100 = 24.51≈25%
Thursday - 35/160×100 =21.87≈22%
Friday - 40/135×100 = 29.62 ≈ 30%

As we can clearly see that there are 3 days on which employes placed the coupon for ≥25%.They are Tuesday, Wednesday, and Friday.

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<h2>Explanation:</h2><h2></h2>

The diagram for this problem is shown below. Point E is the intersection of the two diagonals and we know that:

$\angle BCE=\beta \\ \\ \angle DCE=\theta$

Every internal angle of any rectangle measures 90 degrees, so:

$\beta +\alpha=90 \\ \\ (4x-23)+(5+5x)=90 \\ \\ \\ Isolating \ x: \\ \\ (4x+5x)+(5-23)=90 \\ \\ 9x-18=90 \\ \\ 9x=108 \\ \\ x=\frac{108}{9}=12$

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The sum of internal angles of any triangle add up to 180 degrees, so:

$\beta + \beta+\angle BEC=180^{\circ} \\ \\ 2\beta+\angle BEC=180^{\circ} \\ \\ \angle BEC=180^{\circ}-2\beta \\ \\ \angle BEC=180^{\circ}-2(25^{\circ}) \\ \\ \angle BEC=180^{\circ}-50^{\circ} \\ \\ \boxed{\angle BEC=130^{\circ}}}$

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gyhbgt

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The answer is A.

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Since this is a right triangle you can use The formula: leg squared plus leg squared = hypotenuse squared

So lets square the hypotenuse and first leg
And you get 85 hypotenuse and 49 leg

So just subtract 49 from 85 to get the other leg squares

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