Perimeter of rectangle = 2( length +width)
given: Perimeter=60 ft and width=20 ft
plugging these values in the formula,
60=2(20+ length)
dividing both sides by 2
30=20+length
length =30-20=10
length is 10 feet
width is 20 feet
Area of rectangle is given by:
Area = l*w
Area = 10 *20 = 200 square feet
Answer : Area of rectangle is 200 square feet.
- I think it's possibly this "The figure must be a square because the diagonals of a square bisect the right angles." but there's also "The figure must be a rhombus because it has exactly 2 pairs of congruent angles." buuut since the first one seems more better i'm assuming then that's probably the right answer.
Answer: L = 29cm
Step-by-step explanation:
Let's go!!
To find any rectangle area, you have to apply this formula: A = L . w , where L is the length and w is the width.
So, we have w = L - 13 (the width is 13 less than the Length) and then, perimeter is 90 cm.
Well, I hope you remember that the perimeter of rectangle is 2L + 2W. In this case, 2L + 2w = 90
Then, you might to solve this system of equation:
2L + 2w = 90
w = L - 13
Simplifying the first equation, you'll have L + w = 45 (you can divide everything of 2).
Our new system:
L + w = 45
w = L - 13
Using the substituition method:
L + L - 13 = 45
2L = 58
L = 29 cm
the width is 29 - 13 = 16 cm
Answer:
4.5 sq. units
Step-by-step explanation:
area = -⅓x³+3/2 x² ] 0 to 3
= -⅓(3)³+ 3/2 (3)² -0
= -9 + 27/2
= -9 + 13.5
= 4.5 sq. units
12/3 or the same thing as ur question but just add a division sign, eg. difference of two and one that would be 2-1
