X^2(x-3)+1(x-3)=0
(x^2+1)(x-3)=0
so
x=1 and x= no real roots
Answer: BC = √75 unit
Step-by-step explanation: AB = 10 unit AC = 5 unit
∴ BC = 10² - 5²
= 100 - 25 = 75
BC = √75 unit
Answer:
Step-by-step explanation:
Since they are consecutive angles
You would subtract 180 from 135 to get 45 Measure 2 is 45
I believe it’s (-10,-2). Please let me know if this worked and if not let me know and I’ll try a different way
X=y+1
Least possible value for y(y+1)? Well, it appears for y halfway between the roots (you know what a parabola is, don't you?). That y is -0.5, so let's calculate -0.5*0.5, which is -0.25.
The least possible value is
Well, not really :)) The two values must be both negative, so we can't take one of them to be 0.5! As we lower the values, however, the product grows, reaching 0 when x=0 and y=-1, and further increasing as x and y lower. Thus, we would actually take x=0 and y=-1.