Answer:
16,200 im not sure if its right just multiply everything then add to multiplication x3
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Answer:
12
Step-by-step explanation:
(-2)(-3)(-3+5)
6(2)
12
Merry Christmas :)
The answer is 10 1/2.
First you need to convert 4/5 and 7/10 so the denominator is the same. 4/5=8/10, 7/10 stays the same.
Now we add= 6 8/10 +3 7/10 =9 15/10.
9 15/10=10 5/10=10 1/2.
Hope this helps and hope you have a great day and please make brainiest
