Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.
Given the function is 
and the Rolle's Theorem does not apply to the function.
Rolle's theorem is used to determine if a function is continuous and also differentiable.
The condition for Rolle's theorem to be true as:
- f(a)=f(b)
- f(x) must be continuous in [a,b].
- f(x) must be differentiable in (a,b).
To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.
If we look closely at the given function we can see that the first derivative of the given function is:
![\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Df%28x%29%26%3D%5Csqrt%7B%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E3%7D%5C%5C%20f%28x%29%26%3D%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%20f%27%28x%29%26%3D%5Cfrac%7B3%7D%7B2%7D%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Ccdot%20%5Cfrac%7B2%7D%7B3%7D%5Ccdot%20%28-x%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%20f%27%28x%29%26%3D%5Cfrac%7B-%5Csqrt%7B2-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%5Cend)
From this point of view we can see that the given function is not defined for x=0.
Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.
Learn more about Rolle's Theorem from here brainly.com/question/12279222
#SPJ4
Answer:
Step-by-step explanation:
The first thing that we can do is look at the equation of the line and then worry about the inequality afterwards.
This line has a y-intercept of 4 and a slope of -1.
This means that the equation of this line would be 
Now that we have the equation of the line, we just need to determine which inequality sign to use.
As the shaded region is BELOW the line, we will use a less than (<) sign.
As the line is fully shaded, I can only assume that it is meant to include the line, which would mean that would be the equation for this inequality.
Answer:
153.94
Step-by-step explanation:
A = pi * r^2
A = pi * 7^2 (radius is half of the diameter)
A = 49 * pi
A = 153.94
i hope this helps !!
Answer:
Step-by-step explanation:
here you go mate
step 1
-2(-4x-1)-x+3=−30 equation/Question
step 2
-2(-4x-1)-x+3=−30 distribute
7x+5=-30
step 3
7x+5=-30 subtract 5
7x=-35
step 4
divide
answer
x=-5
Answer:
C. 8
Step-by-step explanation:
![\because \: {s}^{3} = 64 \\ s = \sqrt[3]{64} \\ s = 4 \\ side \: of \: cube = 4 \: units \\ when \: side \: is \: halved \\ new \: side \: length = \frac{4}{2} = 2 \\ \: new \: volume = {2}^{3} = 8 \: cubic \: units](https://tex.z-dn.net/?f=%20%5Cbecause%20%5C%3A%20%20%7Bs%7D%5E%7B3%7D%20%20%3D%2064%20%5C%5C%20s%20%3D%20%20%5Csqrt%5B3%5D%7B64%7D%20%20%5C%5C%20s%20%3D%204%20%5C%5C%20side%20%5C%3A%20of%20%5C%3A%20cube%20%3D%204%20%5C%3A%20units%20%5C%5C%20when%20%5C%3A%20side%20%5C%3A%20is%20%5C%3A%20halved%20%5C%5C%20new%20%5C%3A%20side%20%5C%3A%20length%20%3D%20%20%5Cfrac%7B4%7D%7B2%7D%20%20%3D%202%20%5C%5C%20%20%5C%3A%20new%20%5C%3A%20volume%20%3D%20%20%7B2%7D%5E%7B3%7D%20%20%3D%208%20%5C%3A%20cubic%20%5C%3A%20units)
