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NARA [144]
3 years ago
15

Alfonso scored 1818 points during his last basketball game, which was 40\%40% of the points the entire team scored. The entire t

eam scored points.
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer: 45 points

Step-by-step explanation:

Let the point of the entire team be represented by x.

Alfonso scored 18 points during his last basketball game, which was 40% of the points the entire team scored. This can then be represented in an equation as:

40% of x = 18

40% × x = 18

40/100 × x = 18

0.4 × x = 18

0.4x = 18

x = 18/0.4

x = 45

The team's total point is 45

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Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
If a data set has 20 data values, the number of values in the upper quartile is .
Scorpion4ik [409]
The upper quartile is 5.5
4 0
3 years ago
Read 2 more answers
Help help , Please help! Brainliest if correct! What was the equation of the graph below before it was shifted to the left 1.5 u
patriot [66]

Answer:

Option (D). G(x) = x³ - x

Step-by-step explanation:

Given function is the attachment,

G(x) = (x - 1.5)³ - (x - 1.5)

This function when translated by left by 1.5 units, rule for the translation is,

G(x) → G'(x + 1.5)

Therefore, translated function will be,

G'(x) = (x - 1.5 + 1.5)³ - (x - 1.5 + 1.5)

G'(x) = x³ - x

Therefore, Option (D) will be the answer.

7 0
3 years ago
If the area of the circle is 225pi what is the diameter
Stells [14]

Answer:

30cm

Step-by-step explanation:

Area is πr²

So,

πr²=225π

r=√225

r=15cm

Diameter=2r=30

Maths is easy peasy

8 0
3 years ago
In the circle below, AD is a diameter and AB is tangent at A. suppose mADC=228. Find the measures of mCAB and mCAD. Type your nu
Tju [1.3M]

Answer:

m∠CAB = 66°

m∠CAD = 24°

Step-by-step explanation:

<em>m∠CAB</em>

The given parameters are;

The measure of arc m\widehat{ADC} = 228°

The diameter of the given circle = \overline{AD}

The tangent to the circle = \underset{AB}{\leftrightarrow}

The measure of m∠CAB and m∠CAD = Required

By the tangent and chord circle theorem, we have;

m∠CAB = (1/2) × m\widehat{AC}

However, we have;

m\widehat{AC} + m\widehat{ADC} = 360° the sum of angles at the center of a circle is 360°

∴ m\widehat{AC} = 360° - m\widehat{ADC}

Which gives;

m\widehat{AC} = 360° - 228° = 132°

m\widehat{AC} = 132°

Therefore;

m∠CAB = (1/2) × 132° = 66°

m∠CAB = 66°

<em>m∠CAD</em>

Given that  \overline{AD} is the diameter of the given circle, we have

The tangent, \underset{AB}{\leftrightarrow}, is perpendicular to the radius of the circle, and therefore \underset{AB}{\leftrightarrow} is also perpendicular to the diameter of the circle

∴ m∠DAB = 90° which is the measure of the angle formed by two perpendicular lines

By angle addition property, we have;

m∠DAB = m∠CAB + m∠CAD

∴ m∠CAD =  m∠DAB - m∠CAB

By substitution, we have;

m∠CAD = 90° - 66° = 24°

m∠CAD = 24°

7 0
3 years ago
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