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d1i1m1o1n [39]
3 years ago
7

Celine is playing a game at the school carnival. There is a box of marbles, and each box has a white, a green, a blue, and an or

ange marble. There is also a fair 12-sided die labeled with the numbers 1 through 12. How many outcomes are in the sample space for pulling a marble out of the box and rolling the die?
48

32

16

8
Mathematics
2 answers:
Vladimir [108]3 years ago
8 0
There are four colors of marbles. There are 12 numbers on the dice. There is a 1/4 chance of pulling a specific color marble and a 1/12 chance of rolling a specific color. 1/4 times 1/12 is 1/48. There can be 48 outcomes.
lina2011 [118]3 years ago
7 0

There are 48 possible outcomes.

The first way to figure this problem out is to make a list for all the possible combinations.

(w = white, g = green, b = blue, and o = orange)

1, w; 2, w; 3, w; 4, w; 5, w; 6, w; 7, w; 8, w; 9, w; 10, w; 11, w; 12, w

1, g; 2, ; 3, g; 4, g; 5, g; 6, g; 7, g; 8, g; 9, g; 10, g; 11, g; 12, g

1, b; 2,b; 3, b; 4, b; 5, b; 6, b; 7, b; 8, b; 9, b; 10, b ; 11, b; 12, b

1, o; 2,o; 3,o; 4,o; 5,o; 6, o; 7, o; 8, o; 9,o ;10, o ;11, o 12, o

If you count all of these possibilities, you would come up with 48. Of course, this way takes a very long time, and there is an easier way.

Simply multiply 12 (The number of possibilities on the die) by 4 (The number of possible colors) to get 48.

Therefore, there are 48 possible outcomes in this situation.

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If Hannah gives her younger sister 3 shirts, it does not matter what order she hands them to her. No matter the order, it will still be the same group of 3 shirt. Since order is not important this problem can be solved using a combination.

Specifically we are asked to find 8C3 (sometimes called "8 choose 3"). This is a fraction. In the numerator we start with 8 and count down 3 numbers. In the denominator we start with 3 and count all the way down to 1. Thus we obtain,

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Answer:

\frac{150}{360}  \times \pi \times {3}^{2}  \\ 2.4 \times \pi \times 9 = 11.780 {m}^{2}

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  1) 5x-2y=4.         2) 3x-5y=13  x-2y=5<br>3x+y=9
Natali [406]
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\left\{\begin{array}{ccc}3x-5y=13\\x-2y=5\end{array}\right\\\left\{\begin{array}{ccc}3x-5y=13\\x=2y+5\end{array}\right\\\\substitute:\\\\3(2y+5)-5y=13\\6y+15-5y=13\\y=13-15\\y=-2\\\\x=2\cdot(-2)+5=-4+5=1\\\\Answer:x=1;\ y=-2.
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natta225 [31]

Answer:

5.

Step-by-step explanation:

7 0
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Read 2 more answers
If f(x) = 4(3x - 5), find f-1(x)
deff fn [24]

Answer:

f^{-1}(x) =  \frac{1}{12}(x+20)

Step-by-step explanation:

Given: f(x) = 4(3x - 5)

Is required to find f⁻¹(x)

f(x) = y = 4(3x - 5)

∴ y = 4 * 3x - 4 * 5

∴ y = 12x - 20 ⇒ add 20 to both sides

∴ y + 20 = 12x ⇒ divide both sides by 12

∴ \frac{1}{12} (y+20) = x

Replace the places of x and y.

∴ y=\frac{1}{12} (x+20)

∴ f^{-1}(x) =  \frac{1}{12}(x+20)

7 0
3 years ago
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