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rusak2 [61]
3 years ago
10

Some YRDSB schools are lucky to have access to a track.

Mathematics
1 answer:
omeli [17]3 years ago
5 0

Answer:

Yes they lucky

Step-by-step explanation:

Wait the choices are only one

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Please help me out :)
avanturin [10]

Answer:

answer is B

Step-by-step explanation:

as S and T are points on the same line

8 0
3 years ago
Someone help please
CaHeK987 [17]

Answer:

It would be D

Step-by-step explanation:

7 0
3 years ago
If y = x/k where k is a constant, and y = 5 when x = 30, what is the value of y when x = 60?
Alex777 [14]

Answer:

\huge\boxed{\sf y = 10}

Step-by-step explanation:

<u>Given Equation is:</u>

y = x / k

We know that y = 5 when x = 30

Put it in the above equation

5 = 30 / k

k = 30 / 5

k = 6

<u>Now,</u>

y = ? when x = 60

Put it in the above equation

y = x / k

y = 60 / 6

y = 10

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
Helppppppppppppppppppppppp
Arturiano [62]

Answer:

9.4 x 10^4= 470

hope it helps

8 0
3 years ago
Dale has 2000 dollars to invest. He has a goal to have 5800 in this invest ment in 9 years. At what annual rate compounded conti
elena-14-01-66 [18.8K]

Answer:

Dale will reach his goal at an annual rate of 11.83%.

Step-by-step explanation:

The formula for continuos compounding is given by:

A(t) = Pe^{rt}

In which A is the amount after t years, P is the principal(initial amount) and r is the annual rate.

Dale has 2000 dollars to invest.

This means that P = 2000

He has a goal to have 5800 in this invest ment in 9 years.

So A(9) = 5800

At what annual rate compounded continuously will Dale reach his goal?

This is r.

A(t) = Pe^{rt}

5800 = 2000e^{9r}

e^{9r} = \frac{58}{20}

e^{9r} = 2.9

\ln{e^{9r}} = \ln{2.9}

9r = \ln{2.9}

r = \frac{\ln{2.9}}{9}

r = 0.1183

Dale will reach his goal at an annual rate of 11.83%.

3 0
4 years ago
Read 2 more answers
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