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3 years ago

Some YRDSB schools are lucky to have access to a track.

Mathematics

1 answer:

omeli [17]3 years ago

5 0

Answer:

Yes they lucky

Step-by-step explanation:

Wait the choices are only one

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9x-1=1/2(15x-47) I need help

NikAS [45]

Answer:

The answer is x= -15

6 0

2 years ago

Melody spent 16 days traveling in South America. How many weeks and days did Melody travel in South America?

Genrish500 [490]

Answer: 2 week and 2 days

Step-by-step explanation:

Given

Melody spent 16 days in South America

A week consists of 7 days

In 2 weeks it is, 14 days

So, 16 days is equivalent to 2 weeks and 2 days

Melody spent 2 weeks and 2 days in South America

4 0

3 years ago

Leo works at McDonalds, and gets paid $8.50 hr. He passed his store’s inspection and received a $100 bonus.

Semmy [17]

Answer:

$8.50hr+ $100=x

Step-by-step explanation:

His $8.50 per hour is given to him plus $100 bonus.

7 0

3 years ago

Read 2 more answers

Vickie made a recipe for 144 fluid ounces of scented candle wax. How many 1-cup candle molds can she fill with the recipe

Gre4nikov [31]

there are 0.125 cups inside 1 fluid ounces

144 / 0.125 = 1152 (divide because you are trying to figure out how many of the volumes of the mold can fit inside the 144 fluid ounces

You can fill 1152 molds with 144 fluid ounces

3 0

3 years ago

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

3 years ago