Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Answer: 4,536
Step-by-step explanation: Multiply your two 9's to get 81. Multiply your 8 and 7 to get 56. Multiply 81 and 56 together to get your answer of 4,536.
9 x 9 = 81
8 x 7 = 56
81 x 56 = 4,536
Use long multiplication to evaluate this equation.
I hope this helps you out! ♥
Answer:
y=x + p
Step-by-step explanation:
Answer:
R (t) = 60 - 60 cos (6t)
Step-by-step explanation:
Given that:
R(t) = acos (bt) + d
at t= 0
R(0) = 0
0 = acos (0) + d
a + d = 0 ----- (1)
After seconds it reaches a height of 60 cm from the ground.
i.e
Recall from the question that:
At t = 0, R(0) = 0 which is the minimum
as such it is only when a is negative can acos (bt ) + d can get to minimum at t= 0
Similarly; 60 × 2 = maximum
R'(t) = -ab sin (bt) =0
bt = k π
here;
k is the integer
making t the subject of the formula, we have:
replacing the derived equation of k into R(t) = acos (bt) + d
Since we known a < 0 (negative)
then d-a will be maximum
d-a = 60 × 2
d-a = 120 ----- (3)
Relating to equation (1) and (3)
a = -60 and d = 60
∴ R(t) = 60 - 60 cos (bt)
Similarly;
For
where ;
Then b = 6
∴
R (t) = 60 - 60 cos (6t)