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Ostrovityanka [42]
3 years ago
7

Leroy is a house painter who has just been paid

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
4 0
875 you simply subtract the cost of paint by with Total amount payed. Which is $875
erma4kov [3.2K]3 years ago
3 0

Answer:

960

Step-by-step explanation:

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Alina [70]
Yes with what ? are u single ?
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3 years ago
Factor completely: −3x2 + 6x − 9
denis23 [38]
Factor out the -3
(-3)(x^2-2x+3)

8 0
3 years ago
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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
What’s the answer to 8-(-4)
mash [69]

Answer:

+ 12

Step-by-step explanation:

8 - (- 4) = 8 + 4 = 12

8 0
3 years ago
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The hypotenuse of a right triangle is three times the length of one of its legs. The length of the other leg is four feet. Find
andre [41]

Hello!

It is given information that this triangle is a right triangle, meaning that the Pythagorean Theorem can apply here.

a^2+b^2=c^2

We can set the length of a leg as an unknown variable x.

x^2+4^2=(3x)^2

Remember that it is the whole 3x term being squared, meaning that it'll simplify to 9x^2, not 3x^2.

x^2+16=9x^2

8x^2=16

x^2=2

x=\sqrt{2}

This means we can plug back in to find the sides.

The hypotenuse would be 3\sqrt{2}, or 4.2.

And the legs would be 1.4 and 4, respectively.

Hope this helps!

7 0
3 years ago
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